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Vera_Pavlovna [14]
4 years ago
9

What is the restoring force of a spring with a spring constant of 4a and a stretched displacement of 3b? A. –7 ab B. `-7 a/b ` C

. –12 ab D. `-12 a/b`
Physics
1 answer:
algol134 years ago
3 0

Answer:

C. -12 ab

Explanation:

The restoring force on a spring is given by Hooke's law:

F=-kx

where

k is the spring constant

x is the stretched (or compressed) displacement of the spring

In this problem we have:

k = 4a

x = 3b

Substituting into the equation, we find:

F=-(4a)(3b) = -12 ab

And the negative sign means that the direction of the force (negative) is opposite to the direction of the displacement (positive).

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Makovka662 [10]

Answer:The answer is A

Explanation:

To determine the force, we use the equation

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, where Fg is the force of gravity, G is the gravitational constant,

m1

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m2

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Fg=6.67×10−11 N×m2/kg2×2.5 kg×2.5 kg/(0.50 m)2=1.7×10−9N

. Since this is a gravitational problem, the force on one body has the same force as the other body, but the directions are opposite.

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3 years ago
If the current decreases uniformly from 5.00 a to 2.00 a in 3.00 ms, calculate the self-induced emf in the coil.
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1. Place the following in logical order by writing the numbers 1 through 6 in the spaces provided.
grin007 [14]

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ecdbaf

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4 0
3 years ago
The atmosphere has many roles, including:
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3 0
4 years ago
Two identical vertical springs S1 and S2 have masses m1 = 400 g and m2 = 800 g attached to them. If m1 causes spring S1 to stret
OlgaM077 [116]

Answer:

potential energy = mgh

= 400÷1000 × 10× 4÷100

= 0.4 × 10 × 0.04

=4/10 ×10×4/100

= 4/10 × 4/10

=16/100

= 0.16 joules

m1 (400) stretches 4cm

m1 (100g) stretches 1cm

so, m2(800g) stretches 8 cm

potential energy of m2 = mgh

= 800/1000 ×10×8/100

= 0.8 × 0.8

=8/10 ×8/10

= 64/100

=0.64 joules

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= 1:4 ( answer)

6 0
3 years ago
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