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mafiozo [28]
3 years ago
12

An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of th

e electric force on this electron due to this field?
1.6 × 10-3 newtons
1.4 × 1024 newtons
2.2 × 10-14 newtons
7.4 × 10-13 newtons
4.5 × 1014 newtons
Physics
2 answers:
RSB [31]3 years ago
7 0
F=Eq. Just sub in the values and you are done.
ivann1987 [24]3 years ago
3 0

Answer:

2.2 x 10^-14 N

Explanation:

q = - 1.6 x 10^-19 C

E = 1.4 x 10^5 N/C

The force on a charged particle placed in an electric field is given by

F = q x E

F = - 1.6 x 10^-19 x 1.4 x 10^5 = - 2.24 x 10^-14 N

F = - 2.2 x 10^-14 N

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What is the main fuel consumed in the core of a red giant?<br> a. H<br> b. C<br> c. Fe<br> d. He
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What is the difference between an object’s speed and its acceleration? NO LINKS
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A laser emits light at power 6.20 mW and wavelength 633 nm. The laser beam is focused (narrowed) until its diameter matches the
Ipatiy [6.2K]

Answer:

a) S = 1.69 10⁹ W/m², b)  P = 5.63 Pa , c) F = 20.6 10⁻¹² N

Explanation:

a) The intensity defined as the energy per unit area

    S = U / A

Area of ​​a circle is

    W = 6.2 mw = 6.2 10-3 W

    R = 1080 nm = 1080 10⁻⁹ m  = 1.080 10⁻⁶ m

   A = π R2

   A = π (1,080 10⁻⁶)²

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   S = 1.69 10⁹ W / m²

b) The radiation pressure

   P = 1 / c (dU / dt) / A

   S = (dU / dt) / A

   

   P = S / c

   P = 1.69 10 9 / 3. 108

   P = 5.63 Pa

c) the definition of pressure is force over area

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   F = 5.63 3.66 10⁻¹²

   F = 20.6 10⁻¹² N

d) for this we use Newton's second law

   F = ma

   a = F / m

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