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mafiozo [28]
3 years ago
12

An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of th

e electric force on this electron due to this field?
1.6 × 10-3 newtons
1.4 × 1024 newtons
2.2 × 10-14 newtons
7.4 × 10-13 newtons
4.5 × 1014 newtons
Physics
2 answers:
RSB [31]3 years ago
7 0
F=Eq. Just sub in the values and you are done.
ivann1987 [24]3 years ago
3 0

Answer:

2.2 x 10^-14 N

Explanation:

q = - 1.6 x 10^-19 C

E = 1.4 x 10^5 N/C

The force on a charged particle placed in an electric field is given by

F = q x E

F = - 1.6 x 10^-19 x 1.4 x 10^5 = - 2.24 x 10^-14 N

F = - 2.2 x 10^-14 N

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