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Sergio039 [100]
3 years ago
9

A baseball player hits a ball with a bat. At one moment the force exerted by the bat on the ball is 18,000 N. At that same momen

t, how much force is exerted on the bat by the ball?
a) 18,000 N

b) less than 18,000 N

c) more than 18,000 N
Physics
1 answer:
11111nata11111 [884]3 years ago
5 0

Answer:

Less than 18000N

Explanation:

Given

Force\ Exerted = 18000N

This question will be answered using Newton's third law.

Understanding this law, it implies that reaction force is equal and opposite to the force exerted.

This implies that;

If the force exerted on the ball is 18000N

the force exerted is -18000N

So, the option that answers the question is less than 18000N because -18000N < 18000N

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The universal force that is effective over the longest distance between very massive objects like planets is
fenix001 [56]
The universal force that is effective over the longest distance between very massive objects like planets is Gravity
8 0
3 years ago
Suppose a ball had a potential energy of 5 J when you dropped it.What would be it’s kinetic energy just as it hit the ground?
timama [110]

Answer:

Due to Conservation of Energy just as the ball hits the ground it's potential energy is assumed zero

Therefore disregarding air resistance all energy is converted into potential energy.

So KE = PE  

(5 J)

4 0
3 years ago
Okay i'm totally stuck and nobody I know really gets it either, so i've turned to Yahoo for help :)
OlgaM077 [116]

Here is the rule for see-saws here on Earth, and there is no reason
to expect that it doesn't work exactly the same anywhere else:

                     (weight) x (distance from the pivot) <u>on one side</u>
is equal to
                     (weight) x (distance from the pivot) <u>on the other side</u>.

That's why, when Dad and Tiny Tommy get on the see-saw, Dad sits
closer to the pivot and Tiny Tommy sits farther away from it.

       (Dad's weight) x (short length) = (Tiny Tommy's weight) x (longer length).


So now we come to the strange beings on the alien planet.
There are three choices right away that both work:

<u>#1).</u>
(400 N) in the middle-seat, facing (200 N) in the end-seat.

       (400) x (1)  =    (200) x (2)

<u>#2).</u>
(200 N) in the middle-seat, facing (100 N) in the end-seat.

       (200) x (1)  =    (100) x (2)

<u>#3).</u>

On one side:  (300 N) in the end-seat       (300) x (2) = <u>600</u>

On the other side:
                      (400 N) in the middle-seat  (400) x (1) = 400
           and     (100 N) in the end-seat      (100) x (2) = 200
                                                    Total . . . . . . . . . . . . <u>600</u> 


These are the only ones to be identified at Harvard . . . . . . .
There may be many others but they haven't been discarvard.


5 0
3 years ago
Read 2 more answers
What is the magnitude and direction (right or left) of the
Sunny_sXe [5.5K]

Answer: 12 N to the right

Explanation:

If we calculate the net force acting on the box, we will have:

<u>In y-component:</u>

Fy_{net}=F_{n}+F_{g} (1)

Where F_{n}=12 N is the Normal force, directed upwards and F_{g}=-12 N is the weight of the box (gravity force), directed downwards.

Fy_{net}=12 N-12 N (2)

Fy_{net}=0 N (3) Hence the net force in the vertical component is zero

<u>In x-component:</u>

Fx_{net}=F_{left}+F_{right} (4)

Where F_{left}=-3 N and F_{right}= 15 N

Fx_{net}=-3 N + 15 N (5)

Fx_{net}=12 N (6) This is the net force in the horizontal component

Therefore, the total net force acting on the box is 12 N directed to the right

5 0
3 years ago
In Lesson 20, a magnesium strip was used to ignite the thermite reaction. When magnesium is placed in a flame from a small blow
nadezda [96]

Answer:

2 electrons will be needed by unbound oxygen in order to fill its 2nd shell.

Explanation:

The chemical reaction between magnesium and oxygen gives magnesium oxide as a product.The reaction is chemically represented as:

2Mg(s)+O_2(g)\rightarrow 2MgO(s)

Magnesium is a metal of group-2 with 2 valence electrons.It has atomic number of 12.

[Mg]=1s^22s^22p^63s^2

In order to attain noble gas configuration it will loose two electrons.

[Mg]^{2+}=1s^22s^22p^6

Mg\rightarrow Mg^{2+}+2e^-...[1]

Oxygen is a non metal of group-16 with 6 valence electrons..It has atomic number of 8.

[O]=1s^22s^22p^4

In order to attain noble gas configuration it will gain two electrons.

[O]^{2-}=1s^22s^22p^6

O+2e^-\rightarrow O^{2-}..[2]

2 electrons will be needed by unbound oxygen in order to fill its 2nd shell.

6 0
4 years ago
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