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kykrilka [37]
3 years ago
7

A wave with a period of 0.008 second has a frequency of

Physics
2 answers:
coldgirl [10]3 years ago
8 0

The frequency of a wave is the reciprocal of its period.

A period of 0.008 sec means a frequency of

         1 / 0.008 sec  =  125 per sec .  (125 Hz)

zubka84 [21]3 years ago
4 0

A wave with a period of 0.008 second has a frequency of

1 /.008 = 125 Hz

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What would be the difference between kinetic and potential energy​
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Kinetic energy is the energy possessed by a body due to its motion. Potential energy is the energy possessed by a body due to its position.

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Lora (of mass 54 kg) is an expert skier. She
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The mechanical energy at top =Mechanical energy at bottom

  • Mass=m=54kg
  • Height=h=51m
  • Acceleration due to gravity=g=10m/s^2
  • Velocity=v=2.6m/s

\\ \tt\longmapsto M_{initial}=M_{Final}

  • Final energy at bottom=The kinetic energy

\\ \tt\longmapsto KE=M_{initial}

\\ \tt\longmapsto KE=P.E_{(Top)}+K.E_{(Top)}

\\ \tt\longmapsto K.E=mgh+\dfrac{1}{2}mv^2

\\ \tt\longmapsto K.E=m\left(gh+\dfrac{v^2}{2}\right)

\\ \tt\longmapsto K.E=54\left((10)(51)+\dfrac{2.6^2}{2}\right)

\\ \tt\longmapsto K.E=54\left(510+\dfrac{6.76}{2}\right)

\\ \tt\longmapsto K .E=54(510+3.38)

\\ \tt\longmapsto K.E=54(513.38)

\\ \tt\longmapsto K.E=27722.52J

\\ \tt\longmapsto K.E=27.7KJ

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26. Keenan found the mass of a book to be 4.56*10^ -2 kg . What is the mass of the book in milligrams?​
vagabundo [1.1K]

Taking into account the rule of three for the change of units, the mass of the book is 45600 miligrams.

First of all, the rule of three is a mathematical tool that helps you quickly solve proportionality problems.

Having three known values ​​and one unknown, a proportional relationship is established between all of them in order to find the fourth term of the proportion.

If the relationship between the magnitudes is direct (when one magnitude increases, so does the other; or when one magnitude decreases, so does the other), the rule of three is applied as follows, where a, b and c are known values ​​and x is the unknown to calculate:

a → b

c → x

So: x=\frac{cxb}{a}

Being 1 kg equivalent to 1000000 milligrams, In this case the rule of three is applied as follows: if 1 kg equals 1000000 milligrams, 4.56×10⁻² kg equals how many milligrams?

1 kg → 1000000 milligrams

4.56×10⁻² kg  → x

So:

x=\frac{4.56x10^{-2} kg x1000000 miligrams }{1 kg}

<u><em>x=45600 miligrams</em></u>

In summary, the mass of the book is 45600 miligrams.

Learn more:

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