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3 years ago

A wave with a period of 0.008 second has a frequency of

2 answers:

8 0

The frequency of a wave is the reciprocal of its period.

A period of 0.008 sec means a frequency of

1 / 0.008 sec = 125 per sec . (125 Hz)

zubka84 [21]3 years ago

4 0

A wave with a period of 0.008 second has a frequency of

1 /.008 = 125 Hz

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a. A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 26.7° and the angle of refracti

Diano4ka-milaya [45]

Answer:

(a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

Explanation:

Given that,

Incidence angle = 26.7°

Refraction angle = 18.3°

(a). We need to calculate the refraction of liquid

Using Snell's law

$n=\dfrac{\sin i}{\sin r}$

Put the value into the formula

$n=\dfrac{\sin 26.7}{\sin 18.3}$

$n=1.43$

We need to critical angle for the liquid when surrounded by air

Using formula of critical angle

$C=\sin^{-1}(\dfrac{1}{n})$

Put the value into the formula

$C=\sin^{-1}(\dfrac{1}{1.43})$

$C=44.37^{\circ}$

(b). Given that,

Incidence angle = 37.5°

Speed of light in mineral $v=2.17\times10^{8}\ m/s$

We need to calculate the index of refraction

Using formula of index of refraction

$n=\dfrac{c}{v}$

Put the value into the formula

$n=\dfrac{3\times10^{8}}{2.17\times10^{8}}$

$n=1.38$

We need to calculate the angle of refraction

Using Snell's law

$n=\dfrac{\sin i}{\sin r}$

$\sin r=\dfrac{\sin i}{n}$

Put the value into the formula

$\sin r=\dfrac{\sin 37.5}{1.38}$

$r=\sin^{-1}(\dfrac{\sin 37.5}{1.38})$

$r=26.17^{\circ}$

Hence, (a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

3 0

3 years ago

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What is the most effective means of establishing awareness of hazards in commercial, industrial, and storage facilities with lar

coldgirl [10]

Answer:

C: Contacting the facilities.

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3 years ago

The two conducting rails in the drawing are tilted upwards so they each make an angle of 30.0° with respect to the ground. The v

dolphi86 [110]

Answer:

The current flows through the rod is 14.9 A.

Explanation:

Given that,

Magnetic field = 0.045 T

Mass of aluminum rod = 0.19 kg

Length = 1.6 m

Angle = 30.0°

We need to calculate the force

Using resolving force

$F\cos\theta=mg\sin\theta$

$F=mg\tan\theta$

Put the value into the formula

$F=0.19\times9.8\times\tan30$

$F=1.075\ N$

We need to calculate the current flows through the rod

Using formula of magnetic force

$F=iLB$

$i=\dfrac{F}{LB}$

Put the value into the formula

$i=\dfrac{1.075}{1.6\times0.045}$

$i=14.9\ A$

Hence, The current flows through the rod is 14.9 A.

8 0

3 years ago

I will brainliest if you sub and stay subbed to JD Outdoors & Gaming

almond37 [142]

Answer:

Alright, I will, and thank you for the brainliest!

Explanation:

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3 years ago

Which change in the heat energy content of water occurs when phase from a liquid to a soild

anyanavicka [17]

If I am reading this correct, the energy content would decrease for the liquid to solidify

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3 years ago

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