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3 years ago

If DE=4x+10, EF=2x-1, and DF=9x-15, find DF. * Captionless Image

1 answer:

6 0

Answer: 63

Hopefully the work makes sense but basically you will add equation DE and EF to get 6x+11 then use that equation with DF and solve for x which will get 26/3 then plug it into DF to get 63

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it is a polynomial equation of degree two that can be written in tche form, where a,b, and c are real numbers and a =/

finlep [7]

Answer:

A quadratic function is a second degree polynomial function. The general form of a quadratic function is this: f (x) = ax2 + bx + c, where a, b, and c are real numbers, and a≠ 0.

6 0

2 years ago

Use the discriminant to find the number and type of solution for x^2+6x=-9

likoan [24]

Answer:

D = 0; one real root

Step-by-step explanation:

Discriminant Formula:

$\displaystyle \large{D = {b}^{2} - 4ac}$

First, arrange the expression or equation in ax^2+bx+c = 0.

$\displaystyle \large{ {x}^{2} + 6x = - 9}$

Add both sides by 9.

$\displaystyle \large{ {x}^{2} + 6x + 9 = - 9 + 9} \\ \displaystyle \large{ {x}^{2} + 6x + 9 = 0}$

Compare the coefficients so we can substitute in the formula.

$\displaystyle \large{a {x}^{2} + bx + c = {x}^{2} + 6x + 9 }$

a = 1
b = 6
c = 9

Substitute a = 1, b = 6 and c = 9 in the formula.

$\displaystyle \large{D = {6}^{2} - 4(1)(9)} \\ \displaystyle \large{D = 36 - 36} \\ \displaystyle \large{D = 0}$

Since D = 0, the type of solution is one real root.

6 0

2 years ago

So far this year, the average monthly revenue at Lexington Times is 50,711. That is 5% less than the monthly average was last ye

SOVA2 [1]

53,380 was the average last year .

Step-by-step explanation:

Here we have , So far this year, the average monthly revenue at Lexington Times is 50,711. That is 5% less than the monthly average was last year. We need to find that What was the average last year . Let's find out:

Let the monthly average was last year be x , According to question the average monthly revenue at Lexington Times is 50,711 but , That is 5% less than the monthly average was last year . Following equation for above scenario is :

⇒ $x-\frac{5(x)}{100}=50711$

⇒ $\frac{100x-5x}{100}=50711$

⇒ $\frac{95x}{100}=50711$

⇒ $\frac{95x(100)}{100(95)}=\frac{50711(100)}{95}$

⇒ $x=\frac{50711(100)}{95}$

⇒ $x=53380$

Therefore , 53,380 was the average last year .

7 0

3 years ago

10 Y plus 9Y minus 6Y plus 6Y simplified

Katena32 [7]

10 y plus 9 y minus 6 y plus 6 y

=> 10y + 9y - 6y + 6y
= 10y + 9y - 0 = 19y

4 0

2 years ago

Which expression is equivalent to 6x^2 + 13x + 5?

hodyreva [135]

The signs of the x-term and the constant term are both positive, so the signs of the constants in the binomial factors must be the same and must both be positive. The only offering that meets that requirement is

... C (2x+1)(3x+5)

_____

If you multiply that out, you get 6x² + 10x + 3x + 5 = 6x² +13x +5, as required.

The sign of the constant term is the product of the signs of the constants in the binomial factors: (+1)·(+5). We want a positive sign for the constant, so both binomial factor constants must have the same sign.

When the signs of the binomial factor constants are the same, the x-term constant will match them. Thus, for a positive x-term constant, both binomial factor constants must be positive.

3 0

2 years ago

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