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Delvig [45]
3 years ago
15

If DE=4x+10, EF=2x-1, and DF=9x-15, find DF. * Captionless Image

Mathematics
1 answer:
liq [111]3 years ago
6 0
Answer: 63

Hopefully the work makes sense but basically you will add equation DE and EF to get 6x+11 then use that equation with DF and solve for x which will get 26/3 then plug it into DF to get 63
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find the consecutive even integers such that three times the larger number is 30 more than the smaller one. help :')
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Answer:

12 and 14

Step-by-step explanation:

Let the even integers be x and x+2

three times the larger number is expressed as 3(x+2)

30 more than the smaller one is x + 30

Equating both expressions

3(x+2) = x +30

Find x

3x+6 = x+30

3x-x = 30-6

2x = 24

x = 12

The second integer is 12+2 = 14

Hence the required integers are 12 and 14

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Answer:

The inequality is;

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