Answer:
The bonds between water molecules are easily broken by the strong ions of ionic compounds
I think the correct answer from the choices listed above would be the last option. <span>If a decrease in temperature accompanies a reaction, then energy was absorbed which means that the reaction is endothermic. Hope this answers the question. Have a nice day.</span>
Answer is: t<span>he boiling point will increase as the external pressure is increases.
</span>The boiling point<span> of a substance is the temperature at which the </span>vapor pressure<span> of the </span>liquid<span> equals the </span>pressure<span> surrounding the liquid, at that temperature</span><span> the liquid changes into a vapor.
</span><span>The boiling point of a liquid dependes upon the surrounding environmental pressure.</span><span>
</span>
Answer:
H2O> NH3>CH4
Explanation:
Now let us look at the issue of the approximate bond angles of each specie;
H2O- 104°
NH3 - 107°
CH4 - 109°
We can see that both species are based on a tetrahedron on the basis of electron pair geometry. How ever, we must also remember that lone pairs cause more repulsion around the central metal atom atom and distort the bond angles. Thus, in the presence of lone pairs, molecules depart from the expected shape predicted by valence shell electron pair repulsion theory. Hence, the repulsion of lone pairs in water (2 lone pairs) is greater than the repulsion in ammonia (1 lone pair) and repulsion in ammonia is greater than the repulsion in methane (no lone pair).
I'm pretty sure it would be -87,036
