Answer:
1. B. Increase
2. A. Decrease
Explanation:
To understand this issue, we need to put some values and using the ohm's law we can corroborate the two situations.
Ohm's law:
![V = I*R\\where:\\I = current[A] ampers\\R = resistance [ohms]\\V = voltage [volts]\\](https://tex.z-dn.net/?f=V%20%3D%20I%2AR%5C%5Cwhere%3A%5C%5CI%20%3D%20current%5BA%5D%20ampers%5C%5CR%20%3D%20resistance%20%5Bohms%5D%5C%5CV%20%3D%20voltage%20%5Bvolts%5D%5C%5C)
Now for the voltage we will use V = 110 [V], for resistance R = 10 [ohms]
Replacing the values we have:
![I = \frac{V}{R} \\\\I = \frac{110}{10}\\I= 11 [amp]](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BV%7D%7BR%7D%20%5C%5C%5C%5CI%20%3D%20%5Cfrac%7B110%7D%7B10%7D%5C%5CI%3D%2011%20%5Bamp%5D)
Now let's double the voltage 220 [V]:
Therefore the current will be increased.
Let's do the same for the resistance if originally we have R = 10 [ohms]
![I = \frac{V}{R}\\I = \frac{110}{10} \\I = 11 [amp]\\](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BV%7D%7BR%7D%5C%5CI%20%3D%20%5Cfrac%7B110%7D%7B10%7D%20%5C%5CI%20%3D%2011%20%5Bamp%5D%5C%5C)
Now let's double the resistance 20 [ohms]:
![I=\frac{110}{20}\\I = 5.5 [amp]](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B110%7D%7B20%7D%5C%5CI%20%3D%205.5%20%5Bamp%5D)
Therefore the current will be decreased.
Answer:
In positive feedback mechanism, the output is fed back to the system which further increases the output. Hence, it is known as positive feedback because it amplifies the output.
In the negative feedback mechanism, the output is fed back to the system which further decreases the the output. Hence, it is known as negative feedback because it reduces the output.
True is the correct anwser
Gender and self esteem is the answer