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Nikitich [7]
4 years ago
15

From the edge of a rooftop, you toss a green ball upward with an initial velocity of 10 m/s and a blue ball downwards with the s

ame initial speed. Air resistance is negligible. When they reach the ground below
a. the green ball will be moving faster than the blue ball.
b. the blue ball will be moving faster than the green ball.
c. the two balls will have the same speed.
Physics
1 answer:
Ira Lisetskai [31]4 years ago
6 0

Answer:

c.The two balls will have the same speed.

Explanation:

When two balls green and blue both are moving with initial velocity 10m/s.

The green ball has been tossed  upward and blue ball downwards.

Air resistance is negligible means there is no force which oppose the motion of balls.

When blue balls has been tossed downward then the blue ball will move under the gravity.

When green fall downward then the ball falls under the gravity because there is no air resistance.

Therefore, both balls move with acceleration due to gravity when they wil reach at ground.

Therefore, the velocity of both balls are same.

Hence, the two balls will have the same speed.

Option c is true.

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Which action will cause the magnetic force to push two magnets closer together?
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8 0
2 years ago
Suppose you designed a spacecraft to work by photon pressure. The sail was a completely absorbing fabric of area 1.0 km2 and you
Alekssandra [29.7K]

Answer:

(a) F = 6.14 *10⁻⁴ N

(b) P = 6.14* 10⁻¹⁰ Pa

(c) t = 27.2 min

Explanation:

Area of sail A = 1.0 km² = 1.0 * 10⁶m²

Wavelength of light  λ = 650 nm = 650 * 10⁻⁹ m

Rate of impact of photons R = 1 mol/s = 6.022 * 10²³ photons/s

(a)

Momentum of each photon is Ρ = h/λ = 6.625 * 10⁻³⁴ / 650 * 10⁻⁹

      = 1.0192 * 10⁻²⁷ kg.m/s

Since the photons are absorbed completely, in every collision the above momentum is transferred to the sail.  

Momentum transferred to the sail per second is product of rate of impact of photons and momentum transferred by each photon.

dp/dt = R * h/ λ

This is the force acting on the sail.

F = R * h/λ = 6.022 * 10²³ * 1.0192 * 10⁻²⁷ = 6.14 *10⁻⁴ N

F = 6.14 *10⁻⁴ N

b)

Pressure exerted by the radiation on the sail = Force acting on the sail / Area of the sail

P = F/A =  6.14 * 10⁻⁴ / 1.0 * 10⁶ =  6.14* 10⁻¹⁰ Pa

P = 6.14* 10⁻¹⁰ Pa

c)  

Acceleration of spacecraft a = F/m = 6.14 * 10⁻⁴ /1.0 = 6.14 * 10⁻⁴m/s²

As the spacecraft starts from rest, initial speed u=0,m/s ,

final speed is u = 1.0 m/s after time t  

v = u+at  

t = 1.0 - 0/ 6.14 * 10⁻⁴ =  1629s = 27.2 min

t = 27.2 min

4 0
4 years ago
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