The number of particles of atoms depends on the ratio of their composition in the compound
<h3>Further explanation</h3>
Given
5.432 g of table sugar
Required
moles of sample
moles of C, H and O
number of atoms
Solution
Table sugar : Sucrose : C₁₂H₂₂O₁₁
= 5.432 : 342,3 g/mol
= 0.016
C = 12 x 0.016 = 0.192
H = 22 x 0.016 = 0.352
O = 11 x 0.016 = 0.176
C = 0.192 x 6.02 x 10²³ = 1.16 x 10²³
H = 0.352 x 6.02 x 10²³ = 2.12 x 10²³
O = 0.176 x 6.02 x 10²³ = 1.06 x 10²³
Answer:
A base forms hydroxide ions in water.
Hope this helps
The area was probably covered by water. I think
Here we have to draw the major product in the acid catalysed hydration reaction of 4-ethyl-3,3-dimethyl-1-hexene.
The 4-ethyl-3,3-dimethyl-1-hexene converts to 2-hydroxy-4-ethyl-3,3-dimethyl-1-hexane as a major product by acid catalyzed hydration reaction.
The acid catalyzed hydration of an alkene is the Sn¹ reaction. Where in the first step a carbocation is generated. The stability of the carbocation depends upon the position of the neighboring group having +I inductive effect.
In the next step the water molecule attack the carbocation and the corresponding alcohol is produced.
In 4-ethyl-3,3-dimethyl-1-hexene the carbocation formed in the C₂ position which is more stable than the C₁ position due to presence of the dimethyl and ethyl group in the neighboring position which have strong +I inductive effect. This is absence in C₁ position.
In the next step the water molecule attack the C₂ position to form the alcohol.
4-ethyl-3,3-dimethyl-1-hexene converts to 2-hydroxy-4-ethyl-3,3-dimethyl-1-hexane by acid catalyzed hydration reaction which is the major product along with 1-hydroxy-4-ethyl-3,3-dimethyl-1-hexane as a minor product.
The reaction mechanism is shown in the image.