Answer: b} The exact time when an individual atom will decay can be accurately predicted.
c} After each half-life, the amount of radioactive material is reduced by half.
Explanation:
All radioactive decay follows first order kinetics.
Rate law expression for first order kinetics is given by:
where,
k = rate constant
t = time taken for decay process
a = initial amount of the reactant
a - x = amount left after decay process
Expression for calculating half life, which is the time taken by the half of the reactants to decompose is:
5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).
We can calculate the moles of CaC₂O₄ obtained considering the following relationships.
5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
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Answer:
Explanation:
Given that:
The distillation is carried out at a pressure of 1 atm
The feed harbors 25% mole of methanol (z)
The total moles of feed is usually 100 moles
In the system, we have both methanol and water
Using the total mole balance for the distillation column.
Fz = Lx + Vy
where;
F = amount of feed
z = mole fraction of ethanol (in feed)
L = amount of liquid product out of the column
V = amount of vapor product out of the column
x = mole fraction of methanol out of the liquid
y = mole fraction of methanol out of the vapor.
SO;
(a)
If all the feed is vaporized, then the vapor will likely have the same composition as the feed.
(b)
If no vaporization of the feed takes place, then the bottoms moving out of the column contains the same composition as the feed.
(c)
If 1/3 of the feed is vaporized; then 2/3 of the feed is at the bottom.
The balance equation would be:
Replacing z = 0.25; we have:
0.75 = 2x + y
(d)
If 2/3 of the feed is vaporized;
Then:
replacing z = 0.25
0.75 = x + 2y