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Afina-wow [57]
3 years ago
9

Two liquids, a and b are immiscible. liquid a has a density of 0.89 g/ml. liquid b has a density of 0.72 g/ml. what would you ex

pect to see if you added equal amounts of both liquids to a test tube, shook, and let settle
Chemistry
1 answer:
Burka [1]3 years ago
5 0
In the given above, we have two densities which are 0.89 g/mL and 0.72 g/mL. We are also given that the liquids are immiscible. After the settlement of the liquids, they will form two layers.

The heavier substance, the one which has a higher density will be at the bottom and the lighter substance, the one which has a lower density will be at the top layer.
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This one is correct
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Who's your celebrity crush and why?
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Ian Somerhalder because he's JUST SO fine

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Read 2 more answers
CONCLUSIONS: Suppose a student titrated a sample of monoprotic acid of unknown concentration using a previously standardized sol
Zolol [24]

Concentration of unknown acid is 0.061 M

Given:

Concentration of NaOH = 0.125 M

Volume of NaOH = 24.68 mL

Volume of acid solution = 50.00 mL

To Find:

Concentration of the unknown acid

Solution: Concentration is the abundance of a constituent divided by the total volume of a mixture. The concentration of the solution tells you how much solute has been dissolved in the solvent

Here we will use the formula for concentration:

M1V1 = M2V2

0.125 x 24.68 = 50 x M2

M2 = 0.125 x 24.68 / 50

M2 = 0.061 M

Hence, the concentration of unknown acid is 0.061 M

Learn more about Concentration here:

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3 0
2 years ago
500 mL of water is added to 400 mL of 0.35 M HCl. Find the concentration of the diluted solution.
jarptica [38.1K]

The concentration of diluted solution is 0.16 M

<u>Explanation:</u>

As, the number of moles of diluted solution and concentrated solution will be same.

So, the equation used to calculate concentration will be:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated HCl solution

M_2\text{ and }V_2 are the molarity and volume of diluted HCl solution

We are given:

M_1=0.35M\\V_1=400mL\\M_2=?M\\V_2=(500+400)mL=900mL

Putting values in above equation, we get:

0.35\times 400=M_2\times 900\\\\M_2=\frac{0.35\times 400}{900}=0.16M

Hence, the concentration of diluted solution is 0.16 M

5 0
3 years ago
Match each term to its description. Match Term Definition Excess reactant A) Reactant that can produce more of the product Limit
faust18 [17]

Answer:

Explanation:

A) Reactant that can produce more of the product

Excess reactant:

In a given reaction, the reactant that is in excess supply is the excess reactant. If the amount of the excess reactant is match, more of the product will be produced.

B) Reactant that can produce a lesser amount of the product

Limiting reactant

The limiting reactant restricts the progress of the reaction. It determines the amount of product that can be formed.

C) Amount of product predicted to be produced by the given reactants

Theoretical yield

For a given amount of reactants, the theoretical yield determines the amount of products that can be produced.

5 0
3 years ago
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