Answer:
622.27
Step-by-step explanation:
- $87.45 + (- $24.76) + (-17.29) = $-129.5
$143.87 + $348.90 = $492.77
492.77 - (-129.5) = 622.27
Uhh this isn't very clear but I think the answer would be measurement or something along those lines
Answers are:
16.
-1 - (-4) = 3
17.
-1-1/3 - (-4) = 2-2/3
18.
2 - (-1) = 3
19.
3-1/2 - (-1) = 4-1/2
20.
3-1/2 - 2 .= 1-1/2
21.
3-1/2 - (-1-1/3) = 4-5/6
Step by step: I took one point and subtracted the second point to get the length of each segment. You could also look at the ruler and count from one point to the other.
Remember when you subtract a negative, the two negatives become a positive
This question is incomplete, the complete question is;
Determine if the described set is a subspace. Assume a, b, and c are real numbers.
The subset of R³ consisting of vectors of the form ![\left[\begin{array}{ccc}a\\b\\c\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%5C%5Cb%5C%5Cc%5Cend%7Barray%7D%5Cright%5D)
, where abc = 0
- The set is a subspace
- The set is not a subspace
Answer:
Therefore; The set is not a subspace
Step-by-step explanation:
Given the data the question;
the subset R³;
S = { , where abc = 0 }
we know that a subset of R³ is a subspace if it stratifies the following properties;
- it contains additive identity
- it is closed under addition
- it is closed under scales multiplication
Looking at the properties, we can say that it is not a subspace
As;
u = ![\left[\begin{array}{ccc}1\\1\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
∈ S and v = ![\left[\begin{array}{ccc}0\\1\\1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%5C%5C1%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
∈ S
As 1×1×0=0 0×1×1=0
But u+v = ![\left[\begin{array}{ccc}1+0\\1+1\\0+1\end{array}\right] =](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2B0%5C%5C1%2B1%5C%5C0%2B1%5Cend%7Barray%7D%5Cright%5D%20%3D)
![\left[\begin{array}{ccc}1\\2\\1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C2%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
∉ S as 1×2×1 ≠ 0
Hence, it is not closed under addition.
Therefore; The set is not a subspace
The area of that rectangle is 150 square inches. The result is obtained by using the formula of the perimeter dan area of pictures.
<h3>How to find the perimeter and area of a rectangle?</h3>
A rectangle is a two dimensional shape consisting of four joints. It has also four angle points.
The perimeter and area of a rectangle can be expressed as follows.
P = 2 (w + l)
A = w × l
Where
- P = perimeter of a rectangle
- A = area of a rectangle
- w = width of a rectangle
- l = length of a rectangle
The perimeter of a rectangle is 800 inches. The width of the rectangle is 60% of its length.
From that information, we have:
- P = 800 inches
- w = 60% × l = 0.6l
P = 2(w + l)
800 = 2(0.6l + l)
400 = 1.6l
l = 400/1.6
l = 250 inches
The area of the rectangle is
A = w × l
A = 0.6 l × l
A = 0.6 l²
A = 0.6 × 250
A = 150 square inches
Hence, the area of that rectangle is 150 square inches.
Learn more about rectangle here:
brainly.com/question/15019502
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