We are going to use Avogadro's constant to calculate how many molecules of
carbons dioxide exist in lungs:
when 1 mole of CO2 has 6.02 x 10^23 molecules, so how many molecules in
CO2 when the number of moles is 5 x 10^-2
number of molecules = moles of CO2 * Avogadro's number
= 5 x 10^-2 * 6.02 x 10^23
= 3 x 10^22 molecules
∴ There are 3 x 10^22 molecules in CO2 exist in lungs
The molality of the lithium ions is calculated as 0.906 m
<h3>What is the molality of lithium ions?</h3>
Given that the compound is written as Li₃PO₄, the dissociation of the compound is given by the equation;
Li₃PO₄ -----> 3Li^+ + PO₄^3-
Since there are three mole of lithium ions in the compound, it the follows that the molality of the lithium ions is;
3 * 0.302 m = 0.906 m
Learn more about molality:brainly.com/question/17034043
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The formula for lead chromate is PbCrO4. This is because the Pb is the lead part- it is the first in the formula with one lead atom. Next is CrO4- chromate. It has a negative charge (-2) and it stands for one chromium atom and four oxygen atoms.
Answer:
A. The energy of moving particles near a fire
Explanation: