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maw [93]
3 years ago
14

Consider the positions of barium (Ba), sulfur (S), silicon (Si), and calcium (Ca) on the periodic table. The atoms of which elem

ent require the least amount of energy to give up an electron when forming chemical bonds?
Chemistry
2 answers:
Ray Of Light [21]3 years ago
6 0

The correct answer is

A. Barium      for edge

Rudiy273 years ago
5 0
Element      atomic number       position

Ba              56                             group 2, period 6

Ca              12                             group 2, period 3

S                16                             group 16, period 3

Si               `14                            group 14, period 3


Now, you need to know the properties of the different type of elements and the tendencies on the periodic table.


The metallic elements are, those placed on the left side of the periodic table, are the ones that release an electron more easily, so they will requiere less energy to give it up when forming chemical bonds.


The higher the metallic character the less the energy need to give up an electron.


The metallic character grows as the group number decreases (goes to the left) period increases (goes downward), so among the  elements considered, Barium will require the least amount of energy to give un an electron when forming chemical bonds.
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Elias serves a volleyball at a velocity of 16 m/s. The mass of the volleyball is 0.27 kg. What is the height of the volleyball a
frosja888 [35]

Answer:

2,7 m

Explanation:

You can solve this doing an energy balance:

m*g*h-\frac{1}{2} *m*v^{2} =41,7[J]

Solving this equation to get h:

\frac{41,7- \frac{1}{2} *m*v^{2} }{m*g}=h

Replacing the values and solving brings to 2,7 m

6 0
3 years ago
Read 2 more answers
What is the volume of one mole of any gas at STP?
Vikki [24]
The volume of one mole of any gas at Standard Temperature and Pressure (1 atm and 0 degrees Celsius [273K]) is 22.4 L.
7 0
3 years ago
Boron sulfide, B2S3(s), reacts violently with water to form dissolved boric acid (H3BO3) and hydrogen sulfide gas
Gwar [14]

The equation structure for the above mentioned reaction can be written as  

B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow

<u>Explanation:</u>

Considering the above reaction, When Boron sulfide, reacts with water more violently to form boric acid and hydrogen sulfide gas.

B_{2} S_{3}+H_{2} O \rightarrow H_{3} B O_{3}+H_{2} S \uparrow

In order to balance the equation, we can do as follows.There are 2 B - atoms on both sides of the equation, but only 2 H - atoms, and one O - atom on LHS, so we have to balance it by putting 6 in front of water and 2 in front of Boric acid and 3 in front of hydrogen sulphide gas, so that we have 2 B - atoms, 3 - S atoms, 12 H - atoms on both sides of the equation, and it is balanced. Balanced equation is given as,

B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow

Thus a Balanced equation of the above mentioned reaction is written.

8 0
2 years ago
What is the maximum mass of h2o that can be produced by combining 68.6 g of each reactant?
Sauron [17]
The answer will be 47.5
7 0
2 years ago
A sample of 19 mg of 9-fluorenone is dissolved in 5 mL of diethyl ether. The resulting organic
maks197457 [2]

Answer:

15.70mg would remain

Explanation:

Partition coefficient is used to extract or purify a solute from a solvent selectively to avoid interference from other substances. For the problem, formula is:

Kp = Concentration 9-fluorenone in ether / Concentration of solute in H₂O

After the solute, 9-fluorenone, is extracted with water, the mass that remains in ether is:

(19mg - X)

<em>Where X is the mass that now is in the aqueous phase</em>

Replacing in Kp formula:

9.5 = (19mg - X) / 5mL / (X /10mL)

0.95X = 19mg - X / 5mL

4.75X = 19 - X

5.75X = 19

X = 19 / 5.75

X = 3.30mg

That means 9-fluorenone that remain in the ether layer is:

19mg - 3.30mg =

<h3>15.70mg would remain</h3>
8 0
3 years ago
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