Answer:
D. Na₃X
Explanation:
We have the neutral compound Ba₃(X)₂. <em>The total charge (zero) is equal to the sum of the charges of the ions times the number of ions in the molecule</em>.
3 × qBa + 2 × qX = 0
3 × (+2) + 2 × qX = 0
2 × qX = -6
qX = -3
If we have the cation Na⁺ and X³⁻, a neutral molecule would require 3 Na⁺ and 1 X³⁻. The resulting compound is Na₃X.
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The given
ketone when reacted with base gave
enolate, the enolate formed due to loss of
methylene proton next to carbonyl group. Enolate when treated with
methyle Bromide gave
alpha substituted product.
Strong absorption around 1713 cm⁻¹ in IR spectrum confirms the presence of
Carbonyl group.
The product along with
¹H-NMR values is given below,