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Bingel [31]
4 years ago
11

When you turn on a radio, what type of energy transformation takes place?

Chemistry
1 answer:
Nonamiya [84]4 years ago
8 0

Answer:

Its D

Explanation:

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NaCl + H2SO4 ---&gt; Na2SO4 + HCl<br> Balance the double replacement chemical reaction.
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2NaCl+H2SO4-->Na2SO4+2HCl

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There are two Na on the right, so put a 2 in front of NaCl on the left. This makes 3 Cl also, so put a 2 in front of HCl on the right. There are already 2 H on the left, so the equation is balanced.

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4Fe(s) + 3O2(g) ⟶ 2Fe2O3(g)
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Iron. Fe

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In the reaction C+02 arrow C02 which element is reduced in the reaction? C O2 CO2
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Hippuric acid (HC9H8NO3)(HC9H8NO3), found in horse urine, has pKa=3.62pKa=3.62. Part A Calculate the pHpH in 0.140 MM hippuric a
Oxana [17]

Answer:

The pH in 0.140 M hippuric acid solution is 2.2.

Explanation :

Dissociation constant of the acid = K_a

pK_a=-\log[K_a]

3.62=-\log[K_a]

K_a=2.399\times 10^{-4}

Concentration of hippuric acid = c = 0.140 M

HC_9H_8NO_3\rightleftharpoons C_9H_8NO_{3}^-+H^+

Initially

c           0     0

At equilibrium

(c-x)     x      x

Concentration of acid = c [HC_9H_8NO_3]=0.140 M

Dissociation constant of an acid is given by:

K_a=\frac{[C_9H_8NO_{3}^-][H^+]}{[HC_9H_8NO_{3}]}

K_a=\frac{x\times x}{(c -x)}

2.399\times 10^{-4}=\frac{x\times x}{(0.140 -x)}

Solving for x:

x = 0.005677 M

[H^+]=x = 0.005677 M

The pH of the solution :

pH=-\log[H^+]

pH=-\log[0.005677 M]=2.246\approx 2.2

The pH in 0.140 M hippuric acid solution is 2.2.

6 0
4 years ago
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