When you turn on a radio, what type of energy transformation takes place?

C(p) = 1.065(7.50p) + 20.25

tigry1 [53]

Answer:

I think its 639/80

Explanation:

4 0

3 years ago

A solution is prepared by adding 91.3 g of sodium bromide [NaBr], to 115. g of water. Determine whether the solution is saturate

MrMuchimi

<u>Answer:</u> The given solution is unsaturated solution

<u>Explanation:</u>

We are given:

Solubility of NaBr = 9.19 m

Unsaturated solution is defined as the solution in which more solute particles can be dissolved in the solvent.

Saturated solution is defined as the solution in which no more solute particles can be dissolved in the solvent.

A precipitate is defined as the insoluble salt which is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

There are three conditions:

When $m_{\text{(calculated)}}$ ; the solution is unsaturated
When $m_{\text{(calculated)}}=m_{\text{(given)}}$ ; the solution is saturated
When $m_{\text{(calculated)}}>m_{\text{(given)}}$ ; precipitate will form

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

Where,

$m_{solute}$ = Given mass of solute (sodium bromide) = 91.3 g

$M_{solute}$ = Molar mass of solute (sodium bromide) = 103 g/mol

$W_{solvent}$ = Mass of solvent (water) = 115 g

Putting values in above equation, we get:

$\text{Calculated molality of NaBr}=\frac{91.3\times 1000}{103\times 115}\\\\\text{Calculated molality of NaBr}=7.71m$

As, the calculated solubility is less than the given solubility. So, the solution will be unsaturated.

Hence, the given solution is unsaturated solution

5 0

3 years ago

The involuntary muscles of the arteries are controlled by the_________ system. respiratory,skeletal,nervous,circulaory

Soloha48 [4]

The involuntary muscles of the arteries are controlled by the nervous system. The correct option among all the options that are given in the question is the third option or the penultimate option. these muscles are not directly under the control of any person and so are called involuntary muscles. I hope the answer helps you.

3 0

3 years ago

For the equilibrium, N2O4(g)<----> 2NO2(g), the equilibrium constant Kp = 0.316. Calculate the equilibrium partial pressur

saveliy_v [14]

The equilibrium reaction is

N2O4(g)<----> 2NO2(g)

For reaction

Kp = (pNO2)^2 / pN2O4

Given:

Kp = 0.316

pN2O4 = 3.48 atm

To calculate

pNO2 = ?

0.316 = (pNO2)^2 / 3.48

(pNO2)^2 = 1.0997

pNO2 = 1.049 atm

5 0

3 years ago

Read 2 more answers

2A (g) + Y (g) <-- --> 3C (g) + D (g)

insens350 [35]

Answer:

A. K = 59.5

Explanation:

Hello there!

In this case, since this reaction seems to start moving leftwards due to the fact that neither A nor Y are present at equilibrium, we should rewrite the equation:

3C (g) + D (g) <-- --> 2A (g) + Y (g)

Thus, the equilibrium expression is:

$K^{left}=\frac{[A]^2[Y]}{[C]^3[D]}$