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jeka94
3 years ago
7

Whatvdo you meant by acid and base​

Chemistry
2 answers:
OlgaM077 [116]3 years ago
7 0

Answer:

<h2>Ãcid</h2>

<em>acid, any substance that in water solution tastes sour, changes the colour of certain indicators (e.g., reddens blue litmus paper), reacts with some metals (e.g., iron) to liberate hydrogen, reacts with bases to form salts, and promotes certain chemical reactions (acid catalysis)</em>

<h2><em>Base</em></h2>

<em>A base is a substance that can neutralize the acid by reacting with hydrogen ions. Most bases are minerals that react with acids to form water and salts. Bases include the oxides, hydroxides and carbonates of metals. The soluble bases are called alkalis. Sodium hydroxide is an alkali</em>

<em>hello</em><em> </em><em>you</em><em> </em><em>there</em><em> </em><em>¿</em>

<em>its</em><em> </em><em>may</em><em> </em><em>help</em><em> </em><em>you</em><em> </em><em>¯\_(ツ)_/¯</em>

<em>llxXKHaNZaDaXxll</em>

larisa86 [58]3 years ago
3 0

Answer:

e meri a

Explanation:

Application software is a software which performs special task for user

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Use these words: inherited, instinctive, learned and traits to explain how parents can influence adaptions in their offspring.
Alexeev081 [22]
Parents can influence adaptations to their offspring(s) by inherited traits. Inherited traits may include traits like running fast and/or hopping higher just because of their parents traits some offspring may end up having the same traits which can help them survive in their habitat environment.
Parents can also influence adaptations in their offspring(s) by learned activity from their parents. Learned traits from the parent(s) is an activity a parent teaches their offspring. For example, if their parent teaches their offspring how to hunt, it makes the offspring survive in their habitat environment.
Parents also can influence adaptations in their offspring(s) by instinctive traits. Instinctive traits are traits that are unlearned from the parent, the offspring learns from instinct. For instance, an instinctive trait can be social behaviors in pack animals. They don't need to learn they already have it in them genetically. And with instinctive traits they can adapt and survive.
                               :) !!!HOPED THAT HELPED!!! :)
 
3 0
3 years ago
CO is a primary pollutant.
Anuta_ua [19.1K]

True

Carbon monoxide is a primary pollutant which no odor results from incomplete combustion of fuel. The man sources are gasoline and burning of biomass.

Depending on the source of emission, pollutants can be classified into two groups that is primary and secondary pollutants.

A primary pollutant is emitted in the atmosphere directly from a source. It can be either natural sch as volcanic eruptions, sandstorms or man-made that is due to industrial and vehicle emissions.  Examples of primary pollutants are nitrogen oxides, carbon monoxide and particulate matter.

Secondary pollutant is due to interactions between primary and secondary pollutants. These can be chemical or physical interactions. Examples are photo-chemical oxidants and secondary particulate matter.

Therefore, carbon monoxide CO is a primary pollutant.





7 0
3 years ago
Read 2 more answers
Gaseous ammonia reacts with oxygen in the
KengaRu [80]
INTERNIAOL RECTLEIMUM
7 0
4 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction: P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH
Pie

Answer: -1835 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H_1=+157kJ (1)

P_4(g)+6Cl_2\rightarrow 4PCl_3(g)  \Delta H_2=-1207J (2)

Net chemical equation:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H=? (3)

Multiplying equation (1) by 4,  and reversing we get

4PCl_3(g)+4Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H_4=4\times -157kJ=-628kJ (4)

Adding (2) and (4)

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H_3=\Delta H_2+\Delta H_4=-1207kJ-628kJ=-1835kJ  

Thus enthaply change for the reaction is -1835 kJ.

3 0
4 years ago
The beaker shown below contains a 0.58 M solution of dye in water. How many moles of dye are there in the beaker?
seropon [69]
According to the equation of molarity:

Molarity= no.of moles / volume per liter of Solution

when we have the molarity=0.58 M and the beaker at 150mL so V (per liter) = 150mL/1000 = 0.150 L

by substitution:
∴ No.of moles = Molarity * Volume of solution (per liter)
                        = 0.58 * 0.150 = 0.087 Moles
7 0
3 years ago
Read 2 more answers
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