When a problem says a rigid vessel, it means that volume is constant. At constant V, pressure and temperature are indirectly proportional. We calculate as follows:
P1/T1 = P2/T2
P1/P2 = T1/T2
P1/P2 = 273.15 / 272.15
P1/P2 = 1.00
Hope this helps. Have a nice day.
Answer:
![|D_{depth} |=19.697m](https://tex.z-dn.net/?f=%7CD_%7Bdepth%7D%20%7C%3D19.697m)
Explanation:
To find Depth D of lake we must need to find the time taken to hit the water.So we use equation of simple motion as:
Δx=vit+(1/2)at²
![x_{f}-x_{i}=v_{i}t+(1/2)at^{2}\\ -5.0m=(o)t+(1/2)(-9.8m/s^{2} )t^{2}\\ -4.9t^{2}=-5.0\\ t^{2}=5/4.9\\t=\sqrt{1.02} \\t=1.01s](https://tex.z-dn.net/?f=x_%7Bf%7D-x_%7Bi%7D%3Dv_%7Bi%7Dt%2B%281%2F2%29at%5E%7B2%7D%5C%5C%20%20-5.0m%3D%28o%29t%2B%281%2F2%29%28-9.8m%2Fs%5E%7B2%7D%20%29t%5E%7B2%7D%5C%5C%20-4.9t%5E%7B2%7D%3D-5.0%5C%5C%20t%5E%7B2%7D%3D5%2F4.9%5C%5Ct%3D%5Csqrt%7B1.02%7D%20%5C%5Ct%3D1.01s)
As we have find the time taken now we need to find the final velocity vf from below equation as
![v_{f}=v_{i}+at\\v_{f}=0+(-9.8m/s^{2} )(1.01s) \\v_{f}=-9.898m/s](https://tex.z-dn.net/?f=v_%7Bf%7D%3Dv_%7Bi%7D%2Bat%5C%5Cv_%7Bf%7D%3D0%2B%28-9.8m%2Fs%5E%7B2%7D%20%29%281.01s%29%20%5C%5Cv_%7Bf%7D%3D-9.898m%2Fs)
So the depth of lake is given by:
first we need to find total time as
t=3.0-1.01 =1.99 s
![|D_{depth} |=|vt|\\|D_{depth} |=|(-9.898m/s)(1.99s)|\\|D_{depth} |=19.697m](https://tex.z-dn.net/?f=%7CD_%7Bdepth%7D%20%7C%3D%7Cvt%7C%5C%5C%7CD_%7Bdepth%7D%20%7C%3D%7C%28-9.898m%2Fs%29%281.99s%29%7C%5C%5C%7CD_%7Bdepth%7D%20%7C%3D19.697m)
Answer:We have , a relation in frequency f and wavelength λ of a wave having the velocity v as ,
v=fλ ,
given f=60Hz , λ=20m ,
therefore velocity of wave , v=60×20=1200m/s
<span>3.36x10^5 Pascals
The ideal gas law is
PV=nRT
where
P = Pressure
V = Volume
n = number of moles of gas particles
R = Ideal gas constant
T = Absolute temperature
Since n and R will remain constant, let's divide both sides of the equation by T, getting
PV=nRT
PV/T=nR
Since the initial value of PV/T will be equal to the final value of PV/T let's set them equal to each other with the equation
P1V1/T1 = P2V2/T2
where
P1, V1, T1 = Initial pressure, volume, temperature
P2, V2, T2 = Final pressure, volume, temperature
Now convert the temperatures to absolute temperature by adding 273.15 to both of them.
T1 = 27 + 273.15 = 300.15
T2 = 157 + 273.15 = 430.15
Substitute the known values into the equation
1.5E5*0.75/300.15 = P2*0.48/430.15
And solve for P2
1.5E5*0.75/300.15 = P2*0.48/430.15
430.15 * 1.5E5*0.75/300.15 = P2*0.48
64522500*0.75/300.15 = P2*0.48
48391875/300.15 = P2*0.48
161225.6372 = P2*0.48
161225.6372/0.48 = P2
335886.7441 = P2
Rounding to 3 significant figures gives 3.36x10^5 Pascals.
(technically, I should round to 2 significant figures for the result of 3.4x10^5 Pascals, but given the precision of the volumes, I suspect that the extra 0 in the initial pressure was accidentally omitted. It should have been 1.50e5 instead of 1.5e5).</span>