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iVinArrow [24]
3 years ago
9

A 1.5m wire carries a 7 A current when a potential difference of 68 V is applied. What is the resistance of the wire?

Physics
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Working...

length of wire L = 1.5 m

current I = 7 A

potential difference V = 68 Volt

According to Ohm's Law

V = IR

R = V/I

R = 68/7

R = 9.7 Ω

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<em>The speed of metal block B is 5 m/s after the collision</em>

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<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is  

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P'=m_1v'_1+m_2v'_2+...+m_nv'_n

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m_1v_1+m_2v_2=m_1v'_1+m_2v'_2

The metal block A has a mass of m1=3.2 Kg and moves at v1=4 m/s. Metal block b has a mass of m2=1.6 Kg and is initially at rest v2=0.

After the collision occurs, block A moves at v1'=1.5 m/s. We need to calculate the speed of the metal block B. Solving for v2':

\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}

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\displaystyle v'_2=\frac{3.2*4+1.6*0-3.2*1.5}{1.6}

\displaystyle v'_2=\frac{8}{1.6}

\displaystyle v'_2=5\ m/s

The speed of metal block B is 5 m/s after the collision

8 0
2 years ago
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