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labwork [276]
3 years ago
14

a gas with a mass of 67.24 g occupies 20.00L and 730 mmHg.what is the molar mass of the gas in g/mol?

Chemistry
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

The molar mass is 85.59 g/mol

Explanation:

Given:

m = mass = 67.24 g

V = Volume = 20 L

P = pressure = 730 mmHg

Question: What is the molar mass of the gas, PM = ?

The molecular weight of any susbtance is defined as the amount of mass over the number of moles.

PM=\frac{m}{n}

According to the ideal gas law:

PV=nRT

Clearing the number of moles from the first equation and replacing it in the second

PV=\frac{mRT}{PM} \\PM=\frac{mRT}{PV}

Here,

R = constant = 62.36367 mmHg L/mol K

T = 25°C = 298 K, we assume that the temperature is the standard.

Substituting values:

PM=\frac{67.24*62.36367*298}{730*20} =85.59g/mol

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Name the following compound: CH3 – CH2 – CH2 – CH2 – CH2 – CH2 – CH2 – CH3 octyle octyne octane octene
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Read 2 more answers
A chemical test has determined the concentration of a solution of an unknown substance to be 2.41 M. a 100.0 mL volume of the so
Oksana_A [137]

Answer : The molar mass of unknown substance is, 39.7 g/mol

Explanation : Given,

Mass of unknown substance = 9.56 g

Volume of solution = 100.0 mL

Molarity = 2.41 M

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of unknown substance}\times 1000}{\text{Molar mass of unknown substance}\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

2.41M=\frac{9.56g\times 1000}{\text{Molar mass of unknown substance}\times 100.0mL}

\text{Molar mass of unknown substance}=39.7g/mol

Therefore, the molar mass of unknown substance is, 39.7 g/mol

5 0
3 years ago
A 0.72-mol sample of PCl5 is put into a 1.00-L vessel and heated. At equilibrium, the vessel contains 0.40 mol of PCl3 (g) and 0
astra-53 [7]

Answer:

Equilibrium constant is 0.4

Explanation:

We propose the equilibrium:

                 PCl₅(g)    ⇄    PCl₃(g)   +    Cl₂(g)

Initially    0.72 mol

We have the 0.72 moles of the PCl₅.

React           x                      x                  x

X amount has reacted, so in the equilibrium we have:

               0.72 - x              0.4               0.4

If we initially have 0.72 moles and we have 0.4 moles at the equilibrium, it means that 0.3 moles has been reacted.

Let's make the expression for Kc:

Kc = [PCl₃] . [Cl₂] /  [PCl₅]

Kc =  0.4 . 0.4 / 0.4

Kc = 0.4

4 0
3 years ago
In the reaction, H2SO4. +. H2O -------> HSO4- +. H3O+ The Base is ____________ a H2SO4 b H3O+ c H2O d HSO4-
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The base is H2O because it is accepting an H+ ion.
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