All categories

2 years ago

How many atoms are in 25.8 grams of Hg (mercury)

Chemistry

1 answer:

Nana76 [90]2 years ago

4 0

Answer:

7.74568E22 or 7.74568 * 10^22 atoms

Explanation:

To find this, we first must find the moles of mercury in 25.8 grams. Since the molar mass of Hg is 200.59, we can find moles of Hg from 25.8 / 200.59 = 0.1286

To find the amount of atoms, we must multipy the amount of moles by Avagadro's number.

.1286 * 6.02214076 * 10²³ is 7.74568E22 or 7.74568 * 10^22 atoms

You might be interested in

A solution is prepared by dissolving 23.7 g of cacl2 in 375 g of water. the density of the resulting solution is 1.05 g/ml. the

alekssr [168]

The density of the solution =1.05 g/ml.
The total mass of the resulting solution is = 398.7 g (CaCl2 + water)

Find moles of CaCl2 and water.
Molar mass of CaCl2 = 110 (approx.)

Moles of CaCl2 = 23.7 / 110 = 0.22
so, moles of Cl- ion = 2 x 0.22 = 0.44 (because each molecule of CaCl2 will give two Cl- ions)
Moles of water = 375 / 18 = 20.83

Now, Mole fraction of CaCl2 = (moles of CaCl2) / (total moles)

total moles = moles of Cl- ions + moles of Ca2+ ions + moles of water

= 0.44 + 0.22 + 20.83

=21.49

So, mole fraction = 0.44 / (21.49) = 0.02

Guess what !!! density is not used. No need

4 0

3 years ago

Read 2 more answers

Which Of These Periods Contain Elements With Electrons s,p,d and f orbitals? Periods 1-3 Periods 1-4

Elanso [62]

The answer would be periods 6-7 :)

7 0

3 years ago

Lead (ll) nitride+ammonium sulfate > lead(ll) sulfate + ammonium nitride

Alenkinab [10]

Answer:

$Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N$

Explanation:

Let's rewrite the given word equation in its chemical balanced equation representation:

1. Lead(II) nitride is represented by lead, Pb, in an oxidation state of 2+, while nitride is a typical nitrogen anion with a state 3-. As a result, the lowest common multiple between 2 and 3 is 6, meaning 2 lead cations are needed to balance 3 nitrogen anions: $Pb_3N_2$ .

2. Ammonium sulfate consists of an ammonium cation with a 1+ charge and sulfate anion with a 2- charge, two ammonium cations needed: $(NH_4)_2SO_4$ .

3. Lead(II) sulfate would have one lead cation and one sulfate anion, as they have the same magnitude of charges with opposite signs: $PbSO_4$ .

4. Ammonium nitride would require three amonium cations to balance the nitride anion: $(NH_4)_3N$ .

Let's write the balanced equation:

$Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N$

7 0

3 years ago

Two characteristics used to classify igneous rocks are texture and

kykrilka [37]

Two characteristics used to classify igneous rocks are texture and Mineral Grains

8 0

3 years ago

Read 2 more answers

Which type of circuit can have many loops for resistors (light bulbs) to attach to?

Maslowich

A circuit with many paths for the current to travel through and not simply one is classified as a parallel circuit. Here the circuit can have many loops of resistors or light bulbs that can be attached.

3 0

3 years ago