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kolbaska11 [484]
3 years ago
5

What is the number of moles in 42 g of NaCl?

Chemistry
2 answers:
olganol [36]3 years ago
8 0
B. 0.72 mol NaCl

http://www.convertunits.com/from/grams+NaCl/to/moles
Masja [62]3 years ago
7 0

Answer : The correct option is, (B) 0.72 mole of NaCl

Solution : Given,

Mass of NaCl = 42 g

Molar mass of NaCl = 58.44 g/mole

Formula used :

\text{Moles of NaCl}=\frac{\text{Mass of NaCl}}{\text{Molar mass of NaCl}}

Now put all the given values in this formula, we get the moles of NaCl

\text{Moles of NaCl}=\frac{42g}{58.44g/mole}=0.718moles=0.72moles

Therefore, the number of moles of NaCl is, 0.72 moles

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Given the equation: 2H2 + O2 → 2H2O, how many moles of oxygen are needed to react with 13 moles of hydrogen
bulgar [2K]

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2H2 + O2 = 2H2O

2mol. 1mol. 2mol

2mol reacts with 1mol

13mol reacts with x

x=<u>13mol</u><u> </u><u>×</u><u> </u><u>1mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>2mol</u>

x= <u>13mol</u>

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6 0
2 years ago
What is the empirical formula for a compound if a sample contains 1. 0 g of S and 1. 5 g of O? SO SO3 S2O2 S2O3.
Tcecarenko [31]

The empirical formula of the given compound is \bold{SO_3}.

The correct option is B.

<h3>What is an empirical formula?</h3>

The empirical formula of a chemical compound is the simplest whole-number ratio of atoms contained in the substance.

Given,

1.0 g of S

1.5 g of O

To calculate the empirical formula, we will divide the masses of the elements by their atomic weight.

For sulfur

\bold{\dfrac{1.0}{32} =0.03125\; mol}

For oxygen

\bold{\dfrac{1.5}{16} =0.09375\; mol}

Now, divide the greater value of mole came by the smaller value

\bold{\dfrac{0.09375\; mol}{0.03125\;mol} = 3}

Thus, the empirical formula for the given compound is 1 for S and 3 for O

\bold{SO_3}

Learn more about empirical formula, here:

brainly.com/question/11588623

7 0
2 years ago
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