Answer:
0.1313 g.
Explanation:
- It is known that at STP, 1.0 mole of ideal gas occupies 22.4 L.
- Suppose that hydrogen behaves ideally and at STP conditions.
<u><em>Using cross multiplication:</em></u>
1.0 mol of hydrogen occupies → 22.4 L.
??? mol of hydrogen occupies → 1.47 L.
∴ The no. of moles of hydrogen that occupies 1.47 L = (1.0 mol)(1.47 L)/(22.4 L) = 6.563 x 10⁻² mol.
- Now, we can get the no. of grams of hydrogen in 6.563 x 10⁻² mol:
<em>The no. of grams of hydrogen = no. of hydrogen moles x molar mass of hydrogen</em> = (6.563 x 10⁻² mol)(2.0 g/mol) = <em>0.1313 g.</em>
Answer:
The specific heat of the metal is 0.466 
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
The equation that allows calculating heat exchanges is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case:
- Q= 2330 J
- c= ?
- m= 25 g
- ΔT= 200 °C
Replacing:
2330 J= c*25 g* 200 °C
Solving:

c=0.466 
<u><em>The specific heat of the metal is 0.466 </em></u>
<u><em></em></u>
It allows you to determine the relation between the reactants and the products.