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Anarel [89]
4 years ago
6

A suitcase is pulled 28 feet along a flat sidewalk with a constant upward force of 80 lb at an angle of 23degrees with the horiz

ontal. Calculate the work done.
Physics
1 answer:
Elenna [48]4 years ago
5 0

Answer:

2795.3 J

Explanation:

distance, d = 28 feet = 8.53 m

Force, F = 80 lb = 356 N

Angle, θ = 23°

Work = F x d x cos θ

W = 356 x 8.53 x cos 23

W = 2795.3 J

Thus, the work done is 2795.3 J.

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A spring gun is made by compressing a spring in a tube and then latching the spring at
inn [45]

Answer:

a)v=13.2171\,m.s^{-1}

b)H=8.9605\,m

Explanation:

Given:

mass of bullet, m=4.97\times 10^{-3}\,kg

compression of the spring, \Delta x=0.0476\,m

force required for the given compression, F=9.12 \,N

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F=m.a

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a= acceleration

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we have:

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Using the eq. of motion:

v^2=u^2+2a.\Delta x

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v= final velocity after the separation of spring with the bullet.

v^2= 0^2+2\times 1835\times 0.0476

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(b)

Now, in vertical direction we take the above velocity as the initial velocity "u"

so,

u=13.2171\,m.s^{-1}

∵At maximum height the final velocity will be zero

v=0\,m.s^{-1}

Using the equation of motion:

v^2=u^2-2g.h

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h= height

g= acceleration due to gravity

0^2=13.2171^2-2\times 9.8\times h

h=8.9129\,m

is the height from the release position of the spring.

So, the height from the latched position be:

H=h+\Delta x

H=8.9129+0.0476

H=8.9605\,m

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marusya05 [52]

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3 years ago
True or False:
Leto [7]
True
False
True
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