2 years ago

Correctly round the following number to the whole number 2.35784

Physics

1 answer:

Elina [12.6K]2 years ago

8 0

Answer:2

Explanation:

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Gravitational potential energy can be defined as

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As M=m, then

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Where,

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PART A) As half its initial value is u'=2u, then

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$dU = -\frac{2Gm^2}{R}$

$dKE = -dU$

Therefore replacing we have that,

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Re-arrange to find v,

$v= \sqrt{\frac{Gm}{R}}$

$v = \sqrt{\frac{6.67*10^{-11}*1*10^{28}}{1*10^{12}}}$

$v = 816.7m/s$

Therefore the velocity when the separation has decreased to one-half its initial value is 816m/s

PART B) With a final separation distance of 2r, we have that

$2r = 2*10^3m$

Therefore

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$v = \sqrt{Gm(\frac{1}{2r}-\frac{1}{R})}$

$v = \sqrt{6.67*10^{-11}*10^{28}(\frac{1}{2*10^3}-\frac{1}{10^{12}})}$

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