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Natali5045456 [20]
3 years ago
7

An ellipse has two focal points. One of the focal points is the _____. earth, moon, or Sun

Physics
2 answers:
Rasek [7]3 years ago
6 0

An ellipse has two focal points. One of the focal points is the <u><em>Sun</em></u>.

Because they planets move faster when they are around the sun.

pogonyaev3 years ago
3 0

An ellipse has two focal points. One of the focal points is the sun. The sun is considered as one of the focal points because the planets orbit around the sun in  an elliptical path.



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A wave has a wavelength of 9 mm and a frequency of 14 hertz. What is its speed?
lesantik [10]
Wavespeed = frequency x wavelength
= 14 x 9
= 126 mm/s
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3 years ago
A __________ score allows a researcher to compare scores across different scales.
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The correct answer should be C. standard

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a ball is thrown straight up into the air with a speed of 13 m/s. if the ball has a mass of 0.25 kg, how high does the ball go?
evablogger [386]
<h2>Hello!</h2>

The answer is: 8.62m

<h2>Why?</h2>

There are involved two types of mechanical energy: kinetic energy and potential energy, in two different moments.

<h2>First moment:</h2>

Before the ball is thrown, where the potential energy is 0.

<h2>Second moment: </h2>

After the ball is thrown, at its maximum height, the Kinetic Energy turns to 0 (since at maximum height,the speed is equal to 0) and the PE turns to its max value.

Therefore,

E=PE+KE

Where:

PE=m.g.h

KE=\frac{1*m*v^{2}}{2}

<em>E</em> is the total energy

<em>PE</em> is the potential energy

<em>KE</em> is the kinetic energy

<em>m</em> is the mass of the object

<em>g</em> is the gravitational acceleration

<em>h </em>is the reached height of the object

<em>v</em> is the velocity of the object

Since the total energy is always constant, according to the Law of Conservation of Energy, we can write the following equation:

KE_{1}+PE_{1}=KE_{2}+PE_{2}

Remember, at the first moment the PE is equal to 0 since there is not height, and at the second moment, the KE is equal to 0 since the velocity at maximum height is 0.

\frac{1*m*v^{2}}{2}+m.g.(0)=\frac{1*m*0^{2}}{2}+m.g.h\\\frac{1*m*v_{1} ^{2}}{2}=m*g*h_{2}

So,

h_{2}=\frac{1*m*v_{1} ^{2}}{2*m*g}\\h_{2}=\frac{1*v_{1} ^{2}}{2g}=\frac{(\frac{13m}{s})^{2} }{2*\frac{9.8m}{s^{2}}}\\h_{2}=8.62m}

Hence,

The height at the second moment (maximum height) is 8.62m

Have a nice day!

5 0
3 years ago
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