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Dafna11 [192]
3 years ago
7

A woman performs 2000 J of work in order to push a cart full of groceries 50 meters. How much force did she apply to the cart? *

Physics
2 answers:
GaryK [48]3 years ago
5 0
They will give you 4000
ad-work [718]3 years ago
4 0
They will give you 4000
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What is 1.2 kg converted into mg.<br> I need to know for step by step please?
astra-53 [7]
Here’s a good photo to reference when converting in the metric system.

Each time you move down a step you move the decimal to the right, each time you move up a step you move the decimal to the left.

We are going from 1.2 kg or kilograms, which is at the very top left of the ladder. To get to mg or milligrams, we would have to make six jumps, so we’d move the decimal over six times.

1.2 > 12. > 120. > 1200. > 12000. > 120000. > 1200000.

So our final answer would be 1,200,000mg.
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Sodium Bicarbonate is a common _____
AleksAgata [21]
Sodium bicarbonate is a common base
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3 years ago
A thermogram identifies the warm and cool parts of an object by using
andrew11 [14]
Infrared rays are used in many forms of thermal technology. This is also used in weather reports to find the temperature of the surrounding areas.

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the spring was compressed three times farther and then the block is released, the work done on the block by the spring as it acc
frosja888 [35]

Answer:

The work done on the block by the spring as it accelerates the block is 4kx².

Explanation:

Let initial distance is x.

It was compressed three times farther and then the block is released, new distance is 3x.

The work done in compressing the spring is given by :

W=\dfrac{1}{2}k(x_2^2-x_1^2)

W=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\W=\dfrac{1}{2}k((3x)^2-x^2)\\\\W=\dfrac{1}{2}k((9x^2-x^2)\\\\W=\dfrac{1}{2}k\times 8x^2\\\\W=4kx^2

So, the work done on the block by the spring as it accelerates the block is 4kx².

8 0
3 years ago
A plumber is trying to fix a clog in a vertical pipe, but does not know how far down in the pipe the clog and the water level is
PIT_PIT [208]

Answer:

the shortest distance to the obstruction is 0.431 m

Explanation:

We can see this system as an air column, where the plumber is open and where the water is closed, in the case when he hears the sound there is a phenomenon of resonance and superposition of waves with constructive interference.

For the lowest resonance we must have a node where the water is and a maximum where the plumber is a quarter of the wavelength

       λ = ¼ L

If we are in a major resonance specifically the following resonance. We have a full wavelength plus a quarter of the wavelength

    λ = 4L / 3

The general formula is

    λ = 4L / n            n = 1, 3, 5, 7,…

In addition the wave speed is the product of the frequency by the wavelength

    v = λ f

Let's replace

    v = (4L / n) f

    L = v n / (4 f)

Now we can calculate the depth or length of the air column

If we have the first standing wave n = 1

    L = 340 1 / (4 197)

    L = 0.431 m

If it is the second resonance n = 3

    L = 340 3 / (4 197)

    L = 1.29 m

We can see the shortest distance to the obstruction is 0.431 m

5 0
3 years ago
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