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Zigmanuir [339]
3 years ago
6

What is the sum of all possible values of y if x is a positive integer, xy > 0, and 6x+2y=25?

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
3 0

Option E

The sum of all possible values of y is 20

<em><u>Solution:</u></em>

Given that,

6x + 2y = 25

Where, xy > 0

We have to find the sum of all possible values of y if x is a positive integer

We can use values of x = 1, 2, 3, 4

For x = 5 and above, y will be negative

<em><u>Substitute x = 1 in given equation</u></em>

6(1) + 2y = 25

6 + 2y = 25

2y = 25 - 6

2y = 19

Divide both the sides of equation by 2

y = \frac{19}{2}

<em><u>Substitute x = 2 in given equation</u></em>

6(2) + 2y = 25

2y = 25 - 12

2y = 13

Divide both the sides of equation by 2

y = \frac{13}{2}

<em><u>Substitute x = 3 in given equation</u></em>

6(3) + 2y = 25

2y = 25 - 18

2y = 7

Divide both the sides of equation by 2

y = \frac{7}{2}

<u><em>Substitute x = 4 in given equation</em></u>

6(4) + 2y = 25

24 + 2y = 25

2y = 25 - 24

2y = 1

Divide both the sides of equation by 2

y = \frac{1}{2}

<u><em>Now add all the values of "y"</em></u>

\text{Sum of possible values of y } = \frac{19}{2} + \frac{13}{2} + \frac{7}{2} + \frac{1}{2}\\\\\text{Sum of possible values of y } = \frac{19+13+7+1}{2}\\\\\text{Sum of possible values of y } = \frac{40}{2}=20

Thus sum of all possible values of y is 20

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3x−12≥15<br><br> 2x−5≤9<br><br> 5x+8≤53<br><br> 3x−5≥16
zalisa [80]

Answer:

Step-by-step explanation:

A) 3x−12≥15

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B) 2x−5≤9

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C) 5x+8≤53

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or x ≥ 7

Have a good day!

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Step-by-step explanation:

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