What are the greatest common factors of 21, 2, and 14
2 answers:
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First, we are going to find the distance traveled by the ship adding the tow distances:
Distance traveled= 24 mi +33 mi=57 mi
Next, we are going to use the Pythagorean theorem to find the distance from
to 
:
d^2=1665
mi
Finally, we are going to subtract the two distances:
57 mi -40.8 mi= 16.2 mi
We can conclude that <span>if the ship could have traveled in a straight lime from point a to point c, it could have saved 16.2 miles.</span>
Distance traveled= 24 mi +33 mi=57 mi
Next, we are going to use the Pythagorean theorem to find the distance from
d^2=1665
Finally, we are going to subtract the two distances:
57 mi -40.8 mi= 16.2 mi
We can conclude that <span>if the ship could have traveled in a straight lime from point a to point c, it could have saved 16.2 miles.</span>