Answer:
(a) cesium bromide (CsBr): 9.15 grams
(b) calcium sulfate (CaSO4): 5.85 grams
(c) sodium phosphate (Na3PO4): 7.05 grams
(d) lithium dichromate (Li2Cr2O7): 9.88 grams
(e) potassium oxalate (K2C2O4): 7.15 grams
Explanation:
<u>(a) cesium bromide (CsBr):</u>
Molar mass of CsBR = 212.81 g/mol
Number of moles = molarity * volume
Number of moles = 0.100 M *0.43 L
Number of moles = 0.043 moles
Mass of CsBr required = moles * Molar mass
Mass of CsBr required = 0.043 moles * 212.81 g/mol
Mass of CsBr required = 9.15 grams
<u>(b) calcium sulfate (CaSO4):</u>
Molar mass of CaSO4 = 136.14 g/mol
Mass of CaSO4 required = moles * Molar mass
Mass of CaSO4 required = 0.043 moles * 136.14 g/mol
Mass of CaSO4 required = 5.85 grams
<u>(c) sodium phosphate (Na3PO4):</u>
Molar mass of Na3PO4 = 163.94 g/mol
Mass of Na3PO4 required = moles * Molar mass
Mass of Na3PO4 required = 0.043 moles * 163.94 g/mol
Mass of Na3PO4 required = 7.05 grams
<u>(d) lithium dichromate (Li2Cr2O7):</u>
Molar mass of Li2Cr2O7 = 229.87 g/mol
Mass of Li2Cr2O7 required = moles * Molar mass
Mass of Li2Cr2O7 required = 0.043 moles * 229.87 g/mol
Mass of Li2Cr2O7 required = 9.88 grams
<u>(e) potassium oxalate (K2C2O4):</u>
Molar mass of K2C2O4 = 166.22 g/mol
Mass of K2C2O4 required = moles * Molar mass
Mass of K2C2O4 required = 0.043 moles * 166.22 g/mol
Mass of K2C2O4 required = 7.15 grams
