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1 answer:
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Answer:
They are all formed in acidic solution.
Explanation:
The diagram for hemiacetal, acetal and imine is shown in the diagram below and a star is placed on the three of them since they are all form in acidic solution.
From the diagram; reaction of methanol with propanal leads to formation of hemiacetal. From CH₃OH(methanol), one hydrogen attaches itself to the Oxygen double bond on the propanal to form a new hydroxyl group, the other methoxyl (-O-CH₃) from methanol attaches itself to other part of the propanal.
The further addition of methanol to Hemiacetal yields to Acetal.
Imines are formed by Mannich Reaction which is the reaction of propanal with amine group and which is followed by the dehydration with a Schiff base.
Answer:
1) Exothermic.
2)
3)
Explanation:
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1) In this case, for these calorimetry problems, we can realize that since the temperature increases the reaction is exothermic because it is releasing heat to solution, that is why the temperature goes from 22.0 °C to 28.6 °C.
2) Now, for the total heat released by the reaction, we first need to assume that all of it is absorbed by the solution since it is possible to assume that the calorimeter is perfectly isolated. In such a way, it is also valid to assume that the specific heat of the solution is 4.184 J/(g°C) as it is mostly water, therefore, the heat released by the reaction is:
3) Finally, since the enthalpy of reaction is calculated by dividing the heat released by the reaction over the moles of the solute, in this case LiCl, we proceed as follows:
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