Answer:
21.2 g
Explanation:
Step 1: Given data
- Molar concentration of the solution (C): 0.400 mol/L
- Volume of solution (V): 500 mL (0.500 L)
Step 2: Calculate the moles of Na₂CO₃ (solute) in the solution
We will use the definition of molarity.
C = moles of solute / liters of solution
moles of solute = C × liters of solution
moles of solute = 0.400 mol/L × 0.500 L = 0.200 mol
Step 3: Calculate the mass corresponding to 0.200 moles of Na₂CO₃
The molar mass of Na₂CO₃ is 105.99 g/mol.
0.200 mol × 105.99 g/mol = 21.2 g
Where is the graph at? may you send a picture of it?
The answer is A: the PH scale
The pressure would increase. When the temperature change form cold to hot, the gas will find ways to escape from containment. Thus, if it cannot escape that pressure will keep on increasing as the temperature rises.
Answer:
16:1
Explanation:
Atoms of element X weigh 32 times more than atoms of element Y. We can write this in a symbolic way.
mX = 32 mY [1]
where,
- mX and mY are the masses of X and Y, respectively
A compound has the formula: XY₂, that is, in 1 molecule of XY₂ there is 1 atom of X and 2 atoms of Y. The ratio of the mass of X to the mass of Y in this compound equals:
mX/2 mY [2]
If we substitute [1] in [2], we get:
mX/2 mY = 32 mY/2 mY = 16 = 16:1
