Answer:
The answer to your question is given below.
Explanation:
We'll begin by converting 100 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
100 mL = 100 mL × 1 L / 1000 mL
100 mL = 0.1 L
Next, we shall determine the number of mole of NaCl in the solution. This can be obtained as follow:
Volume of solution = 0.1 L
Molarity of NaCl = 0.250 M
Mole of NaCl =?
Molarity = mole / Volume
0.250 = mole of NaCl / 0.1
Cross multiply
Mole of NaCl = 0.250 × 0.1
Mole of NaCl = 0.025 mole
Finally, we shall determine the mass of 0.025 mole of NaCl. This can be obtained as follow:
Mole of NaCl = 0.025 mole
Molar mass of NaCl = 23 + 35.5
= 58.5 g/mol
Mass of NaCl =?
Mole = mass / Molar mass
0.025 = mass of NaCl /58.5
Cross multiply
Mass of NaCl = 0.025 × 58.5
Mass of NaCl = 1.46 g
Thus, to prepare the solution, weigh out 1.46 g of NaCl and dissolve in 1 L of water.
