If velocity is positive, which would most likely yield a negative acceleration?
2 answers:
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Answer:
Explanation:
Hello,
In this case, for the given reaction, the equilibrium constant turns out:
Nonetheless, we are asked for the reverse equilibrium constant that is:
Which is greater than one.
In such a way, the Gibbs free energy turns out:
Now, since the reverse equilibrium constant is greater than zero its natural logarithm is positive, therefore with the initial minus, the Gibbs free energy is less than zero, that is, negative.