Answer:
Explanation:
We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.
M_r: 84.01
H₂SO4 + 2NaHCO₃ ⟶ Na₂SO₄ + 2CO₂ + 2H₂O
n/mol: 6
1. Use the molar ratio of NaHCO₃ to calculate the moles of NaHCO₃.
2. Use the molar mass of NaHCO₃ to calculate the mass of NaHCO₃.
You must use of NaHCO₃.
White is the answer to this
<span>Primarily what causes water to conduct electricity are the ions present in the water itself.</span>
175.8 g NaCl to moles:
(175.8 g)/(58.44 g/mol) = 3.008 mol NaCl
Molarity = moles of solute/volume of solution in liters
(3.008 mol NaCl)/(1.5 L) = 2.0 M.
The molarity of this solution would be 2.0 M.