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Levart [38]
2 years ago
13

1.4=0.7p solve the equation

Mathematics
2 answers:
MatroZZZ [7]2 years ago
7 0
All you need to do if divide 0.7 from both sides. So like this 

1.4=0.7p 
/0.7= 0.7 
and 0.7 cancels out so just figure out 1.4 divided by 0.7. 
You should get 2


WINSTONCH [101]2 years ago
4 0
You need to isolate p:
1.4 divided by 0.7 = 0.7p divided by 0.7 (this eliminates 0.7)
2 = p
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In a experiment, the probability that event A occurs is 5/9, the probability that event B occurs is 5/7, and the probability tha
Ymorist [56]

Answer:

52.5% probability that A occurs given B occurs

Step-by-step explanation:

Suppose we have two events, A and B, the conditional probability formula is:

P(A|B) = \frac{P(A \cap B)}{P(B)}

In which

P(A|B) is the probability of A happening given that B happened.

P(A \cap B) is the probability of both A and B happening.

P(B) is the probability of B happening.

In this problem, we have that:

P(A \cap B) = \frac{3}{8}, P(B) = \frac{5}{7}

So

P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{\frac{3}{8}}{\frac{5}{7}} = 0.525

52.5% probability that A occurs given B occurs

7 0
3 years ago
I NEED help with my homework. I don’t get it
DIA [1.3K]
Help with what part I can help
7 0
3 years ago
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Latita had 12 marbles. she gave 2 marbles to her friend she has 10/12 of her marbles left write answer in simplest form
zloy xaker [14]
The answer would be 5/6.
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3 years ago
Help solving this math question
olga_2 [115]

22. B) $65,000,000 per year.

23. B) Education.

Step-by-step explanation:

Step 1; To find the average rate of change in annual budget between the two given years. We divide the difference in values for the two years by the period in between the two years. In 2008, the budget was $358,708,000 while in 2010 it was $488,106,000. The period in between was 2 years i.e 2009 and 2010.

The average rate of change = \frac{488,106,000-358,708,000}{2} = \frac{129,398,000}{2} = $64,699,000 per year.

So the average rate of change was $64,699,000 which approximately equals option B. $65,000,000.

Step 2; To find the human resources program's 2007 to 2010 ratio we divide the value in 2007 to the value in 2010. To find the other similar ratio, we divide the value in 2007 to the value in 2010 for all the other programs and determine which is closest to the human resources program.

Human resources program ratio = \frac{4,051,050}{5,921,379} = 0.6841,

Agricultural / natural resources ratio = \frac{373,904}{488,106} = 0.766,

Education's ratio = \frac{2,164,607}{3,008,036} = 0.7196,

General government's ratio = \frac{14,347,325}{14,716,155} = 0.9749,

Highways and transportation's ratio = \frac{1,468,482}{1,773,893} = 0.827,

Public safety's ratio = \frac{263,463}{464,233} = 0.5675.

The Human resources' program ratio is 0.6841 and the closest is Education's ratio which is 0.7196. So education is the answer.

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2 years ago
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