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ser-zykov [4K]
3 years ago
7

Define the law conservation of mass​

Chemistry
1 answer:
denis23 [38]3 years ago
7 0

Answer:

Explanation:

The law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as the system's mass cannot change, so the quantity can neither be added nor be removed.

hope it helps

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Which model of the atom explains the orbitals of electrons as waves
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Answer:

The Bohr model of the atom explains the reactivity of all atoms.

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What is the total mass of solute in 1000. grams of a solution having a concentration of 5 parts per million?
Art [367]

50 grams or 50,000 mili grams  is the mass of solute in 1000 grams of a solution having a concentration of 5 parts per million.

Explanation:

Total mass of solution = 1000 grams or 1000 ml since 1 gram = 1 ml

concentration is 5 parts per million ( 5 mg in 1000 ml solution or 0.005 gram in 1000 ml)

the formula used for parts per million:

parts per million = \frac{mass of solute (mg)}{volume of solution}

putting the values in the equation:

parts per million = \frac{mass of solute}{volume of solvent}

0.005 x 1000 = mass of solute

50 grams= mass of solute

converting this into mg

50,000 mg. is the total mass of solute in 5ppm of 1000 ml solution.

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3 years ago
How could Mendeleev predict the properties of elements that had not yet been discovered?
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3 years ago
Which of the following statements about minerals and ores is true?
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3 0
2 years ago
Determine the empirical formula of the following compound if a sample contains 0.104 molK, 0.052 molC, and 0.156 molO;?
faltersainse [42]

Answer:

K₂CO₃    

Explanation:

Given parameters:

Number of moles of K = 0.104mol

Number of moles of C = 0.052mol

Number of moles of O = 0.156mol

Method

From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.

Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.

  • Divide the given moles through by the smallest which is C, 0.052mol.
  • Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio.
  • This is the empirical formula

Solution

Elements                             K                       C                    O

Number of moles            0.104                0.052            0.156

Dividing by the

smallest                       0.104/0.052     0.052/0.052  0.156/0.052

                                            2                           1                     3

The empirical formula is K₂CO₃      

3 0
3 years ago
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