Ask question

Ask question

All categories

2 years ago

9

37.5ml of menthol is dissolved in water to make 456 ml of solution, what is the concentration expressed in volume/volume % of th

e solute?

1 answer:

Ahat [919]2 years ago

3 0

Answer:

V/V% = 8.2%

Explanation:

Given data:

Volume of methanol = 37.5 mL

Volume of solution = 456 mL

V/V% = ?

Solution:

V/V% = [volume of solute / volume of solution ]×100

V/V% = 37.5 mL / 456 mL × 100

V/V% = 0.08× 100

V/V% = 8.2%

You might be interested in

PLS HELP ME IT IS SUPPOSED TO BE DONE IN 10 MINS PLS In a two paragraph (it can be a 2 sentence paragraph) extended response, su

zheka24 [161]

Answer:

Environment: They must be supplied and used in ways that have minimal safety and environmental stewardship have advanced safety regulations and practices, promulgated rules for reducing VOC emissions from oil and gas production and ... disposal protocols are similarly reducing negative impacts to air and water.

Explanation:

8 0

3 years ago

An ethylene glycol solution contains 21.4 g of ethylene glycol (C2H6O2) in 97.6 mL of water. (Assume a density of 1.00 g/mL for

8090 [49]

Answer: The freezing point and boiling point of the solution are $-6.6^0C$ and $101.8^0C$ respectively.

Explanation:

Depression in freezing point:

$T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = freezing point of solution = ?

$T^o_f$ = freezing point of water = $0^0C$

$k_f$ = freezing point constant of water = $1.86^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_f=-6.6^0C$

Therefore,the freezing point of the solution is $-6.6^0C$

Elevation in boiling point :

$T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^0C$

$k_b$ = boiling point constant of water = $0.52^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_b=101.8^0C$

Thus the boiling point of the solution is $101.8^0C$

4 0

3 years ago

What is the relationship between the word pairs in this analogy? dull: boring as amusing: entertaining O A. Synonyms O B. Antony

leva [86]

Answer:

A: Synonyms

Explanation:

Synonyms are two words that have same meaning but are different words (tell me if this works!)

8 0

2 years ago

Read 2 more answers

Uranium has an atomic weight of 238 amu.

shepuryov [24]

Answer:

U= 238g/mol

U2O5= 556g/mol

Explanation:

Since U= 238

O=16

U3O5= 2(238)+3(16)=556g/mol

4 0

3 years ago

If the products of a certain reaction are favored (i.e., the ΔG value of the reaction is negative), one would expect a significa

Over [174]

Answer:

positive H and negative S

Explanation:

For a reaction to be spontaneous, the absolute best combination is a negative Delta H and a positive Delta S. When they are both positive, the reaction is only spontaneous at higher temperatures. When they are both negative, the reaction is only spontaneous at lower temperatures. and again if a catalyst is added to the reaction, the activation energy is lowered because a lower-energy transition state is formed. The catalyst does not affect the energy of the reactants or products (and thus does not affect ΔG).

So from these discussions

Ea does not affect G value at all (whether +Ea or -Ea).

And for product to be formed the reaction should be spontaneous, where H is negative and S positive else the reaction will yield low product.

4 0

3 years ago

Read 2 more answers