Which histone helps stabilize the solenoid structure?

Consider the following intermediate chemical equations. 2 equations. First: upper C (s) plus one half upper O subscript 2 (g) ri

Dmitrij [34]

The oxygen in the final equation appears as reactant Upper O subscript 2 (g). Thus, option A is correct.

The chemical equations are the representation of the chemical formula involved in the equation as the reactant and the formed product.

<h3>What will be the form of oxygen?</h3>

The given chemical equations are:

$\rm C\;(s)\;+\;\frac{1}{2}\;O_2\;(g)\rightarrow\;CO\;(g)$
$\rm CO\;(g)+\;\frac{1}{2}\;O_2\;(g)\rightarrow\;CO_2\;(g)$

The final chemical equation formed for the formation of Carbon dioxide is the sum of the two equations.

The final equation is achieved by substituting equation 1 in equation 2.

$\rm C\;(s)\;+\;\frac{1}{2}\;O_2\;(g)\;+\;\dfrac{1}{2}\;O_2\;(g)\;\rightarrow\;CO_2\;(g)\\\\ C\;(s)\;+\;O_2\;(g)\;\rightarrow\;CO_2\;(g)$

The oxygen in the final equation appears as reactant Upper O subscript 2 (g). Thus, option A is correct.

Learn more about the final equation, here:

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3 0

2 years ago

Read 2 more answers

A 25.0 ml solution of .0600 M EDTA was added to a 57.0 ml sample containing an unknown concentration of V3+. All V3+ present for

Rom4ik [11]

Explanation:

Let us assume that the ratio for the given reaction is 1:1.

Therefore, we will calculate the moles of $Ga^{3+}$ as follows.

Moles of $Ga^{3+}$ solution = molarity × volume (L)

= 0.0440 M × 0.014 L

= 0.000616 moles

Moles of excess EDTA = 0.000616 moles

Also, the initial moles of EDTA will be calculated as follows.

Total initial moles of EDTA = 0.0600 M × 0.025 L

= 0.0015

Therefore, moles of EDTA reacted with $V^{3+}$ will be as follows.

= 0.0015 - 0.000616

= 0.00088 moles

Since, we have supposed a 1 : 1 ratio between $V^{3+}$ and EDTA .

So, moles of $V^{3+}$ = 0.00088 moles

Now, we will calculate the molarity of $V^{3+}$ as follows.

Molarity of $V^{3+}$ solution = $\frac{\text{moles}}{\text{volume (L)}}$

= $\frac{0.00088 moles}{0.057 L}$

= 0.015 M

Thus, we can conclude that the original concentration of the $V^{3+}$ solution is 0.015 M.

4 0

3 years ago

A chemist needs to neutralize 25.5 L of 3.86 M chloric acid (HClO3). What mass of sodium hydroxide is

Karolina [17]

Answer:

3.94 × 10³ g

Explanation:

Step 1: Write the neutralization reaction

HClO₃ + NaOH = NaClO₃ + H₂O

Step 2: Calculate the moles of chloric acid that react

25.5 L of 3.86 M chloric acid is to be neutralized. The reacting moles are:

$25.5L \times \frac{3.86mol}{L} =98.4mol$

Step 3: Calculate the required moles of sodium hydroxide

The molar ratio of HClO₃ to NaOH is 1:1. Then, the reacting moles of NaOH are 98.4 moles.

Step 4: Calculate the mass of sodium hydroxide corresponding to 98.4 moles

The molar mass of NaOH is 40.00 g/mol.

$98.4mol \times \frac{40.00g}{mol} =3.94 \times 10^{3} g$

6 0

3 years ago

The compound tyrosine contains 59.66% C, 6.12% H, 7.73% N, and 26.49% O by mass. What is the empirical formula of tyrosine?

ycow [4]

Answer: C9H11O3N

Explanation:

The percentage by mass of each element is divided by its relative atomic mass. The lowest ratio is now observed. Each ratio is now divided by this lowest ratio and approximated to whole numbers. All these are shown in detail in the image attached.

6 0

4 years ago

Why does an increase in temperature typically cause an increase in rate of reaction?

Alja [10]

Answer:

c

Explanation:

because it decrese the activation energy

6 0

3 years ago