Which histone helps stabilize the solenoid structure?

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Alexus [3.1K]

Explanation:

biosphere

that is the answer

7 0

3 years ago

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1.674×10-4 mol of an unidentified gaseous substance effuses through a tiny hole in 86.6 s. Under identical conditions, 1.715×10-

siniylev [52]

<h2>Answer:</h2>

44.06 g/mol

<h3>Explanation:</h3>

We are given;

Number of moles of unidentified gas as 1.674×10^-4 mol
Time of effusion of unidentified gas 86.6 s
Number of moles of Argon gas as 1.715×10^-4 mol
Time of effusion of Argon gas is 84.5 s

We are supposed to calculate the molar mass of unidentified gas

<h3>Step 1: Calculate the effusion rates of each gas</h3>

Effusion rate = Number of moles/time

Effusion rate of unidentified gas (R₁)

= 1.674×10^-4 mol ÷ 86.6 s

= 1.933 × 10^-6 mol/s

Effusion rate of Argon gas (R₂)

= 1.715×10^-4 mol ÷ 84.5 sec

= 2.030 × 10^-6 mol/s

<h3>Step 2: Calculate the molar mass of unidentified gas</h3>

Assuming the molar mass of unidentified gas is x;
We can use the Graham's law of effusion to find x;
According to Graham's law of diffusion;

$\frac{R_{1}}{R_{2}}}=\frac{\sqrt{MM_{Ar}}}{\sqrt{X}}$

But, Molar mass of Argon is 39.948 g/mol

Therefore;

$\frac{1.933*10^-6mol/s}{2.030*10^-6mol/s}}=\frac{\sqrt{39.948}}{\sqrt{X}}$

$0.9522=\frac{\sqrt{39.948}}{\sqrt{X}}$

Solving for X

x = 44.06 g/mol

Therefore, the molar mass of the identified gas is 44.06 g/mol

3 0

4 years ago

Convert 150 g/L to the unit g/mL.<br><br> 15,000 g/mL<br> 15 g/mL<br> 0.15 g/mL<br> 0.0015 g/mL

fredd [130]

1 g/L ------- 0.001 g/mL
150 g/L ----- ?

150 x 0.001 / 1

= 0.15 g/mL

Answer C

6 0

4 years ago

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(b) Which peak, the one at 365 nm or the one at 435 nm, results from the absorption of

GenaCL600 [577]

Answer:

365nm and Exothermic reaction

Explanation:

b) The Einstein Planck's equation states that

E = hf where E is the energy of a photon

h is the Planck's constant

f is the frequency

But Frequency f = c/λ where c is the speed of light

λ is the wavelength

Therefore Energy E = hc/λ

From the above equation we see that the Energy of a photon is indirectly proportional to its wavelength

Hence as the wavelength increases from 365nm to 435nm, the energy of the photons decreases

Therefore, a photon will wavelength 365nm would have a higher energy than one will wavelength of 435nm.

c) From the diagram we observe the following:

At high temperatures, HPR⁺ occurs at a higher concentration than at low temperatures.

At low temperatures, more of PR⁻ is formed than at high temperatures

The equation of the reaction is

HPR⁺ (aq) ⁺ ⇆ H⁺ + PR⁻(aq)

Le Chartelier's principle states that when an external constraint such as a change in concentration, pressure or temperature is placed on a system in equilibrium, the system acts in such a way as to oppose the change.

Hence a decrease in temperature on the side of reactant, HPR would force the equilibrium to the side of the products, PR in other to accommodate the change

The forward reaction, which produces more of the product PR⁻ is exothermic because the at low temperatures, the the forward reaction is favoured and equilibrium shifts to the right.

5 0

3 years ago

Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction

inessss [21]

Answer:

Explanation:

2 NH4I + Pb(NO3)2 = PbI2 + 2 NH4NO3

2 mol 1 mol

x ml 751 ml

0.550 M 0.380 M

0.380 mol/1000 ml x 751 ml = 0.285 mol Pb(NO3)2

0.285 mol Pb(NO3)2 x 2 mol NH4I/1 mol Pb(NO3)2=0.571 mol NH4I needed

0.571 mol NH4I/0.550 mol/1000 ml=1038 ml

6 0

3 years ago