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emmainna [20.7K]
3 years ago
10

What information is needed to determine the amount of moles in 1.6g of HCL?

Chemistry
1 answer:
alukav5142 [94]3 years ago
8 0

Answer:

Molar mass and Mass

Explanation:

The relationship between mass and number of moles is given as;

Number of moles = Mass / Molar mass

Mass = 1.6 g

Molar mass of HCl = ( 1 + 35.5 ) = 36.5 g/mol

Number of moles = 1.6 g / 36.5 g/mol

Number of moles = 0.0438 mol

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A chemist titrates of a hypochlorous acid solution with solution at . Calculate the pH at equivalence. The of hypochlorous acid
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The question is incomplete, here is the complete question:

A chemist titrates 110.0 mL of a 0.2412 M hypochlorous acid (HCIO) solution with 0.0613 M NaOH solution at 25°C. Calculate the pH at equivalence. The pKa of hypochlorous acid is 7.50. Round your answer to 2 decimal places

<u>Answer:</u> The pH of the solution is 10.09

<u>Explanation:</u>

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n_1M_1V_1=n_2M_2V_2

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n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HClO

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

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n_1=1\\M_1=0.2412M\\V_1=110.0mL\\n_2=1\\M_2=0.0613M\\V_2=?mL

Putting values in above equation, we get:

1\times 0.2412\times 110.0=1\times 0.0613\times V_2\\\\V_2=\frac{1\times 0.2412\times 110.0}{1\times 0.0613}=432.8mL

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To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}     .....(1)

  • <u>For HClO:</u>

Molarity of HClO solution = 0.2412 M

Volume of solution = 110.0 mL

Putting values in equation 1, we get:

0.2412M=\frac{\text{Moles of HClO}\times 1000}{110}\\\\\text{Moles of HClO}=\frac{(0.2412\times 110)}{1000}=0.026532mol

  • <u>For NaClO:</u>

Moles of NaClO = 0.026532 moles

Volume of solution = [432.8 + 110] mL = 542.8 mL

Putting values in above equation, we get:

\text{Molarity of NaClO}=\frac{0.026532\times 1000}{542.8}=0.0489M

To calculate the pH of the solution, we use the equation:

pH=7+\frac{1}{2}[pK_a+\log C]

where,

pK_a = negative logarithm of weak acid which is hypochlorous acid = 7.50

C = concentration of the salt = 0.0489 M

Putting values in above equation, we get:

pH=7+\frac{1}{2}[7.50+\log (0.0489)]\\\\pH=7+3.09=10.09

Hence, the pH of the solution is 10.09

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