Which of the following will likely result in a misfolded protein (mark all that apply)?

1 answer:

3 0

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below are the choice that should accompanied your question above:

1) Mutation resulting in aberrant STOP codon
2) Mutation in DNA sequence
3) Mutation in splice site
4) Mutation in promoter

I think the answer should be

1) Mutation resulting in aberrant STOP codon
2) Mutation in DNA sequence

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Explanation:

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What's the oxidation # of P in P4O8

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You are given a sample of several compounds to separate by paper chromatography. You draw a pencil line exactly 1.00 cm from the

grandymaker [24]

Answer:

a. 6.57 cm

b. 8.17 cm

c. 0.80

Explanation:

a. The compound moved from where it was first placed, to a spot 7.57 cm from the bottom of the paper, in other words:

7.57 cm - 1.00 cm = 6.57 cm

b. A similar method is made for the solvent:

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c. The Rf of the factor is equal to the distance that the compound moved divided by the distance the solvent moved:

6.57 cm / 8.17 cm = 0.80

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How many grams of sodium oxide can be produced when 55.3 g Na react with 64.3 g O2?. . Unbalanced equation: Na + O2 → Na2O. . Sh

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this is a limiting reagent problem.

first, balance the equation
4Na+ O2 ---> 2Na2O

use both the mass of Na and mass of O2 to figure out how much possible Na2O you could make.
start with Na and go to grams of Na2O

55.3 gNa x (1molNa/23.0gNa) x (2 molNa2O/4 molNa) x (62.0gNa2O/1molNa2O) = 75.5 gNa2O

do the same with O2

64.3 gO2 x (1 molO2/32.0gO2) x (2 molNa2O/1 mol O2) x (62.0gNa2O/1molNa2O) = 249.2 g Na2O

now you must pick the least amount of Na2O for the one that you actually get in the reaction. This is because you have to have both reacts still present for a reaction to occur. So after the Na runs out when it makes 75.5 gNa2O with O2, the reaction stops.

So, the mass of sodium oxide is

75.5 g

3 0

3 years ago

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