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2 years ago

Which set of ordered pairs represents a function?

Mathematics

2 answers:

Georgia [21]2 years ago

6 0

Answer:

the second one

Step-by-step explanation:

in order for it to be a function the x values CANNOT repeat.

in answer a the x value -6 repeats so that cannot be a function

in answer b none of the x values repeat so its probably this one but lets check the other ones just in case

in answer c the x value 8 repeats so it cannot be this one

in answer d the x value -2 repeats so it cant be this one \

b is the only one that does have repeating x values therefore it is the second one

Damm [24]2 years ago

3 0

B is the answer hope i helped

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PLEASE HELP

lilavasa [31]

Those two functions just miss each other so there are no real solutions. Every polynomial with complex coefficients has complex solutions.

$2x^2 + 2 = 3x$

$2x^2 - 3x = -2$

$2( x^2 - \frac 3 2 x) = -2$

$x^2 - \frac 3 2 x = -1$

$x^2- \frac 3 2 x+ (\frac 3 4)^2= -1 + (\frac 3 4 )^2$

$(x - \frac 3 4)^2 = -\frac 7{16}$

$x - \frac 3 4 = \pm \sqrt{ -\frac 7{16}}$

$x = \frac 3 4 \pm \frac i 4 \sqrt{7}$

$x = \frac 1 4(3 \pm i \sqrt{7})$

4 0

2 years ago

Work out, giving your answer in its simplest form: 5/ 14 x 7/ 30

Elena L [17]

X in (-oo:+oo)

((5/14)*x^7)/30 = 0

1/84*x^7 = 0 // : 1/84

x^7 = 0

x = 0

x = 0

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