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2 years ago

13

Polygon ABCD is translated to create polygon A'B'C'D. Point A and is located at (1, 5) and point A' is located at (-2, 1). What

is the distance from B to B' ?

1 answer:

Ilia_Sergeevich [38]2 years ago

7 0

$\sqrt{ 3^{2}+4^{2} } =5.$
the distance is 5.
hope it helps.

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$x^2+y^2-8x-6y+24=0\quad|-24\\\\(x^2-8x)+(y^2-6y)=-24$

Complete the square:

$x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2$

And we have:

$(x^2-8x)+(y^2-6y)=-24\\\\(x^2-8x+4^2)-4^2+(y^2-6y+3^2)-3^2=-24\\\\
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3 years ago

PLEASE HELP ME IM DESPERATE

Andrews [41]

Answer:

y = - $\frac{1}{2}$ x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - $\frac{1}{2}$ , thus

y = - $\frac{1}{2}$ x + c ← is the partial equation

To find c , substitute (4, - 5) into the partial equation

- 5 = - 2 + c ⇒ c = - 5 + 2 = - 3

y = - $\frac{1}{2}$ x - 3 ← equation of line

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2 years ago