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Alchen [17]
3 years ago
9

When constructing an inscribed regular hexagon, what steps come after six arcs are created on the circle? Connect every other in

tersection of an arc and the circle with a segment. Connect the intersections of the diameters and the circle with a segment. Connect every intersection of an arc and the circle with a segment. Connect the midpoint of the radius to the endpoint of the diameter.
Mathematics
2 answers:
Dominik [7]3 years ago
8 0

Answer:

I also think its B

Step-by-step explanation:

Amiraneli [1.4K]3 years ago
7 0

Answer:

b i think

Step-by-step explanation:

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If a line contains the point (0, -1) and has a slope of 2, then which of the following points also lies on the line?
lana66690 [7]

Answer:

(1,1)

Step-by-step explanation:

3 0
3 years ago
Using Newton's Method, what is the formula for determining the nth term in a sequence of approximations to a solution of a polyn
lorasvet [3.4K]

Step-by-step explanation:

in newton rapson method

x_{n+1}=x_{n}-\frac{f\left(x_{n}\right)}{f^{\prime}\left(x_{n}\right)}

Let n=n-1

x_{(n-1)+1}=x_{n-1}-\frac{f\left(x_{n-1}\right)}{f^{\prime}\left(x_{n-1}\right)}

x_{n}=x_{n-1}-\frac{f\left(x_{n-1}\right)}{f^{\prime}\left(x_{n-1}\right)}

7 0
2 years ago
The value, in dollars, of an antique has increased exponentially over x years as shown in the graph. Estimate the y-intercept of
Aleksandr-060686 [28]

Answer:

The answer is C.

Step-by-step explanation:

I just did the test and the answer was C

3 0
3 years ago
Read 2 more answers
Help please hurry i need done in 20 minutes
klemol [59]

Answer:

OKAY I WAS STRESSING FOR A QUICK MINUTE THINKING I WAS GETTING SOMETHING WRONG BUT THINK THE ANSWER IS CORRECT

So Cos0= 15/64 (SIMPLIFIED) or in decimal form 0.234375

Step-by-step explanation:

7/8² is 49/64 or (in decimal form) 0.765625

1 - 0.765625 = 0.234375

8 0
2 years ago
Help is appreciated! Thanks!
sukhopar [10]

Answer:

  1. 16√3
  2. -45+15i
  3. √255
  4. 6√2 +3√10

Step-by-step explanation:

1)

-4i\sqrt{-48}=-4i\sqrt{(-1)(4^2)(3)}=(-4i)(4i)\sqrt{3}=16\sqrt{3}

__

2)

(-5-5i)(3-6i)=-5(3-6i)-5i(3-6i)=-15+30i-15i+30i^2=-15-30+15i\\\\=-45+15i

__

3)

\sqrt{3}\sqrt{5}\sqrt{17}=\sqrt{3\cdot 5\cdot 17}=\sqrt{255}

__

4)

\sqrt{3}(\sqrt{24}+\sqrt{30})=\sqrt{3\cdot 24}+\sqrt{3\cdot 30}=\sqrt{6^2\cdot 2}+\sqrt{3^2\cdot 10}\\\\=6\sqrt{2}+3\sqrt{10}

_____

The applicable identities are ...

\sqrt{a^2b}=a\sqrt{b}\\\\i^2=-1

7 0
3 years ago
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