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kotykmax [81]
2 years ago
6

Flammability is a material’s ability to burn in the presence of

Chemistry
1 answer:
frosja888 [35]2 years ago
5 0

Answer:

Flammability is a material’s ability to burn in the presence of <u><em>oxygen.</em></u>

Explanation:

Flammability can be described as the ability of a substance to get ignited. Flammability will lead to fire or combustion. Some substances are highly flammable like Benzene. Other tend to be just flammable. And there are also compounds which will nor be flammable at all as they won't react with oxygen. Examples of these substances include helium, steel or glass.

The flammability of a substance shall be considered a very important aspect when storing or transporting a substance.

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An unknown solid acid has a formula h2x. How could you determine the molar mass of the unknown acid for a titration with 0.455 m
Goshia [24]

Answer:

The answer is in the explanation.

Explanation:

A titration of H₂X with KOH produce:

H₂X + 2KOH → 2H₂O + K₂X

It is possible to obtain the moles of H₂X because the moles of KOH are the spent volume of the titration in liters × 0,455M. As for a complete titration of H₂X moles you need twice moles of KOH you know the moles of KOH obtained are half H₂X moles.

As you know the mass of the solid acid that you titrate and molar mass of acid is:

mass of acid / moles of acid. You can determine the molar mass of the unknown acid.

I hope it helps!

3 0
3 years ago
How does the temperature and pressure change inside the earth, moving downward from the crust to the core?
Rus_ich [418]

B. Both temperature and pressure increase

8 0
2 years ago
Read 2 more answers
Which of the following categories of small bodies in the solar system does Ceres belong to?
Natalija [7]
Ceres is a dwarf planet, so A.
4 0
2 years ago
Somebody help with A B and C please will give brain thanks
Norma-Jean [14]

Answer:

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Explanation:

7 0
2 years ago
What will be the volume occupied by 2.5 moles of nitrogen gas exerting 1.75 atm of pressure at 475K?
Marina86 [1]

Answer:

THE VOLUME OF THE NITROGEN GAS AT 2.5  MOLES , 1.75 ATM AND 475 K IS 55.64 L

Explanation:

Using the ideal gas equation

PV = nRT

P = 1.75 atm

n = 2.5 moles

T = 475 K

R = 0.082 L atm/mol K

V = unknown

Substituting the variables into the equation we have:

V = nRT / P

V = 2.5 * 0.082 * 475 / 1.75

V = 97.375 / 1.75

V = 55.64 L

The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L

6 0
3 years ago
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