molar mass of NaCl-58.5g so B)1.00 mol
Lol now way he answers this
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Answer:
Mass of Ca(OH)₂ required = 0.09 g
Explanation:
Given data:
Volume of HNO₃ = 25 mL (25/1000 = 0.025 L)
Molarity of HNO₃ = 0.100 M
Mass of Ca(OH)₂ required = ?
Solution:
Chemical equation;
Ca(OH)₂ + 2HNO₃ → Ca(NO)₃ + 2H₂O
Number of moles of HNO₃:
Molarity = number of moles / volume in L
0.100 M = number of moles / 0.025 L
Number of moles = 0.100 M ×0.025 L
Number of moles = 0.0025 mol
Now we will compare the moles of Ca(OH)₂ with HNO₃ from balance chemical equation.
HNO₃ : Ca(OH)₂
2 : 1
0.0025 : 1/2×0.0025 = 0.00125
Mass of Ca(OH)₂:
Mass = number of moles × molar mass
Mass = 0.00125 mol × 74.1 g/mol
Mass = 0.09 g
Based on concentration of solute particles and hence the osmotic pressure the solutions can be classified into three categories , with respect to other solutions
a) isotonic: when concentration of one of the solution is same as of the other solution then they are referred as isotonic to each other.
b) hypertonic: When concentration of the solution is greater than the concentration of other solution then it is said to be hypertonic.
c) hypotonic: when concentration of the solution is lesser than the concentration of other solution then it is said to be hypotonic.
So a solution with high concentration of solute will have higher osomotic pressure and will called to have high pressure or tone hence called as hypertonic.
Thus compartment A will have high concentration and will called as hypertonic while the compartment B will have low concentration and will called as hypotonic