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Georgia [21]
3 years ago
12

Scientists must be curious, honest, creative open minded skeptical , ethical and aware of bias. list 3 ways thinking like a scie

ntist can help u in everyday life when doing things like shopping for a new bike,baking a cake, or reading a magazine??
Chemistry
1 answer:
Otrada [13]3 years ago
5 0

Answer:

Explanation:

Thinking like a scientist can help me make daily rational decisions between my wants. In that the way I see want would be ultimately to satisfy the most pressing of needs. This is where the open minded nature of scientist will come in. A scientist would rather chose to buy a new bike than going on expensive dates in order to cut and save travel time.

Thinking like a scientist can help me save cost on actually going out there to buy a cake or making one myself. This is the creative aspect of being a scientist. Why have the ingredient and the skill and I will still choose to go out there buy a cake?

A scientist reads a magazine with all mind seeking to establish the bias that might be laden in an edition. This will help him to rationale between different information presented on the pages of the paper. He/she would question the information source and not believe the story completely.

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Ancient Romans built often out of bricks and mortar. A key ingredient in their mortar was quicklime (calcium oxide), which they
velikii [3]

The question has missing information. At part 1 it is "Write a balanced chemical equation, including physical state symbols, for the decomposition of solid calcium carbonate (CaCO3) into solid calcium oxide and gaseous carbon dioxide."

Part 2. "Suppose 19.0 L of carbon dioxide gas are produced by this reaction, at a temperature of 290.0°C and pressure of exactly 1 atm. Calculate the mass of calcium carbonate that must have reacted (...)"

Answer:

41.0 g

Explanation:

1. Calcium oxide has molecular formula CaO and carbon dioxide CO₂, thus, the reaction will be:

CaCO₃(s) → CaO(s) + CO₂(g)

The equation is already balanced because there's the same number of each element on both sides.

2. First, let's calculate the number of moles of CO₂ produced by the ideal gas law:

PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.082 atm.L/mol.K), and T is the temperature (290°C = 273 = 563 K).

1*19 = n*0.082*563

46.166n = 19

n = 0.4116 mol

By the stoichiometry of the reaction:

1 mol of CaCO₃ ------ 1 mol of CO₂

x ----- 0.4116 mol

By a simple direct three rule:

x = 0.4116 mol of CaCO₃.

The molar mass of the calcium carbonate is 100 g/mol, thus the mass (m) is the number of moles multiplied by it:

m = 0.4116*100

m = 41.16 g = 41.0 g

4 0
3 years ago
If the equilibrium concentrations of products are much greater than those of reactants in this system, what would be the magnitu
miss Akunina [59]

Answer:

K > 1.

Explanation:

∵ The equilibrium constant K = [products]/[reactants].

Since, [products] > [reactants].

<em>∴ The equilibrium constant K > 1.</em>

5 0
4 years ago
Ifa dozen nails weighs 1 pound, how many nails are in 7.6 pounds?
NikAS [45]
Then there should be mostly 91 nails
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3 years ago
Which best describes the effect of j.j Thomson's discovery
goblinko [34]
The accepted model of the atom was changed. JJ Thomson discovered the electrons and performed experiment using the cathode ray tube. The model before his did not have electrons so the model was changed. Hope this helps
3 0
3 years ago
A compound contains only carbon, hydrogen, and oxygen. combustion of 11.75 mg of the compound yields 17.61 mg co2 and 4.81 mg h2
Ymorist [56]

Number of moles is defined as the ratio of given  mass in g to the molar mass.

First, convert the given mass of carbon dioxide in mg to g:

1 mg = 0.001 g

17.61 mg = 0.01761 g

Number of moles of carbon dioxide = \frac{0.01761 g}{44.01 g/mol}

= 0.0004001 mol

Mass of carbon  = number of moles of carbon dioxide \times molar mass of carbon

= 0.0004001 mol\times 12.011 g/mol

= 0.004806 g

Number of moles of water= \frac{0.00481 g}{18 g/mol}

= 2.672\times 10^{-4}

Since, water contains two hydrogen atoms. Thus,

Moles of hydrogen = 2\times 2.672\times 10^{-4}

= 5.34\times 10^{-4}

Mass of hydrogen = 5.34\times 10^{-4}\times \times 1.008 g/mol

= 5.34\times 10^{-4} g

Mass of oxygen = 0.001175-(5.38\times 10^{-4}g+0.004806 g)

= 0.006405 g

Number of moles of oxygen = \frac{0.006405 g}{15.999 g/mol}

= 0.000400

Now,

C_{0.0004001}  H_{0.000534}  O_{0.000400}

Divide the smallest number to get the whole number,

C_{\frac{0.0004001}{0.000400}}  H_{\frac{0.000534}{0.000400}}  O_{\frac{0.000400}{0.000400}}

we get,

C_{1}  H_{1.33}  O_{1}

Now, multiply all the subscript by 3 to get the whole number,

C_{3}     H_{4}      O_{3}   (empirical fomula)

Molar mass of the compound  =3\times 12.011 g/mol+4\times 1.008 g/mol+3\times 15.999 g/mol

= 88.062 g/mol

Divide given molar mass of the compound with the molar mass of the compound.

=\frac{176.1 g/mol}{88.062 g/mol}

= 1.999\simeq 2

Thus, multiply the subscripts of empirical formula by 2 to get the molecular formula, we get:

C_{6}H_{8}O_{6}

Hence, empirical formula is C_{3}H_{4}O_{3} and molecular formula is C_{6}H_{8}O_{6}



8 0
3 years ago
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