Question

Congratulations! You’ve recently received a promotion from work. Your new job is to fill rooms with certain gases. A room is found to measure 9.00 feet wide by 12.0 feet long and 10.0 feet high. Your first assignment is to fill this room with a gas that has a density of 0.88543 kg/m3. Unfortunately your boss is asking you to make the gas (if you know what I mean). How many grams of this gas are required to fill the room? (1m3 = 35.3147 ft3) (Round to the appropriate sig fig)

Answer 1

The amount of gas required to fill the room is 27076.4 g

To calculate the grams of the gas that will fill the room, we make use of the formula below

⇒ Formula:

• D = m/V....................... Equation 1

⇒ Where:

• D = Density of the gas
• m = mass of the gas
• V = Volume of the room

⇒ make m the subject of the equation

• m = DV................... Equation 2

From the question,

⇒ Given:

• D = 0.88543 kg/m³
• V = Volume of a cubiod = Length×Width×Height = 9×12×10 = 1080 ft³

⇒ Converting the volume from ft³ to m³

• V = 1080/35.3147
• V = 30.58 m³

Substitute these values into equation 2

• m = 0.88543(30.58)
• m = 27.0764 kg
• m ≈ 27076.4 g

Hence, The amount of gas required to fill the room is 27076.4 g

Learn more about density here: brainly.com/question/11107994