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BlackZzzverrR [31]
3 years ago
5

If the equilibrium concentrations of products are much greater than those of reactants in this system, what would be the magnitu

de of the equilibrium constant, K,? K < 1 K = 1 K > 1
Chemistry
1 answer:
miss Akunina [59]3 years ago
5 0

Answer:

K > 1.

Explanation:

∵ The equilibrium constant K = [products]/[reactants].

Since, [products] > [reactants].

<em>∴ The equilibrium constant K > 1.</em>

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one reaction that produces hydrogen gas can be represented by the unbalanced chemical equation Mg(s)+HCI(aq) -&gt; MgCI(aq)+H2(g
Sonbull [250]
<h3>Answer:</h3>

128 g HCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Reaction Mole Ratios
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg (s) + HCl (aq) → MgCl (aq) + H₂ (g)

↓

[RxN - Balanced] 2Mg (s) + 2HCl (aq) → 2MgCl (aq) + H₂ (g)

[Given] 3.25 mol Mg

[Solve] x g HCl

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Mg → 2 mol HCl

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of HCl - 1.01 + 35.45 = 36.46 g/mol

<u>Step 3: Stoich</u>

  1. [S - DA] Set up:                                                                                                 \displaystyle 3.25 \ mol \ Mg(\frac{2 \ mol \ HCl}{2 \ mol \ Mg})(\frac{36.46 \ g \ HCl}{1 \ mol \ HCl})
  2. [S - DA] Multiply/Divide [Cancel out units]:                                                    \displaystyle 127.61 \ g \ HCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

127.61 g HCl ≈ 128 g HCl

3 0
2 years ago
What specific electrophile does benzene attack when it undergoes nitration??
Deffense [45]
<span><span>The reaction is as follows:
        C6H6   </span>+   HNO3   +      H2SO4     ------------> </span>C6H5NO2<span>   +   H</span>2<span>O
(BENZENE) (NITRIC ACID)(CATALYST)
</span>NO2(+) is the electrophile that acctacks on the benzene ring in nitration process.
7 0
3 years ago
What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.0×1015Hz?
Anvisha [2.4K]
In order to emit electrons, the cesium will have to absorb photons. Each photon will knock out one electron by transferring its energy to the electron. Therefore, by the principle of energy conservation, the energy of the removed electron will be equal to the energy of the incident photon. That energy is calculated using Planck's equation:

E = hf

E = 6.63 x 10⁻³⁴ * 1 x 10¹⁵
E =  6.63 x 10⁻¹⁹ Joules

The electron will have 6.63 x 10⁻¹⁹ Joules of kinetic energy
3 0
3 years ago
A 1.0 mol sample of which of the following compounds has the greatest mass?
Sholpan [36]

Answer:

D) N2O5

Explanation:

The molar mass of a substance is defined as the mass of this substance in 1 mol. To solve this question we must find the molar mass of each option:

<em>Molar mass NO:</em>

1N = 14g/mol*1

1O = 16g/mol*1

14+16 = 30g/mol

<em>Molar mass NO2:</em>

1N = 14g/mol*1

2O = 16g/mol*2

14+32 = 46g/mol

<em>Molar mass N2O:</em>

2N = 14g/mol*2

1O = 16g/mol*1

28+16 = 44g/mol

<em>Molar mass N2O5:</em>

2N = 14g/mol*2

5O = 16g/mol*5

28+80 = 108g/mol

That means the compound with the greatest mass is:

<h3>D) N2O5</h3>
5 0
3 years ago
Need help on both #19 and #20 please
ziro4ka [17]
This is the answer to question 19. If it’s not clear, send me a message.

5 0
3 years ago
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