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3 years ago

Which best describes the effect of j.j Thomson's discovery

1 answer:

3 0

The accepted model of the atom was changed. JJ Thomson discovered the electrons and performed experiment using the cathode ray tube. The model before his did not have electrons so the model was changed. Hope this helps

You might be interested in

Which half-reaction correctly represents reduction?

Neko [114]

Answer: B. Ca2+ + 2e- ---------> Ca

Explanation:

Reduction involves the gaining of electrons as well as a decrease in the oxidation state of the atom or ion.

In this case; Ca2+ gains two electrons and the oxidation state is reduced from +2 to 0.

Ca2+ + 2e- ---------> Ca

5 0

3 years ago

For the following molecules, what is the order of Bronsted acidity, from highest to lowest

tankabanditka [31]

Answer:

Rank these compounds in order of increasing basicity. (Least basic to most basic)

a. C, B, A

b. B, A, C

c. C, A, B

d. A, B, C

ANSWER: d

I did the quiz already **spoil alert ace that quiz baby heck yea**

Explanation:

If u need proof that its correct the image below with help!

-Good Luck Today

4 0

3 years ago

Which of the following is similar among all living organisms on Earth?

statuscvo [17]

A. cellular function

hope this helps :)

5 0

3 years ago

The reaction can be described using the equation: 2C2H25O24CO22H2O. How much C2H2is needed to react with 68.1 g of O2to produce

Sophie [7]

Answer:

22.13g

Explanation:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Next, we'll calculate the mass of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H2 = (12x2) + (2x1)

= 24 + 2 = 26g/mol

Mass of C2H2 that reacted from the balanced equation = 2 x 26 = 52g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 5 x 32 = 160g

Now, we can obtain the mass of C2H2 that will react with 68.1g of O2 as follow:

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Therefore, Xg of C2H2 will react with 68.1g of O2 i.e

Xg of C2H2 = (52x68.1)/160

Xg of C2H2 = 22.13g

Therefore, 22.13g of C2H2 is needed to react with 68.1g of O2

8 0

3 years ago

A solution of H2SO4(aq) with a molal concentration of 4.80 m has a density of 1.249 g/mL. What is the molar concentration of thi

Naddika [18.5K]

Imagine we have mass of solvent 1kg (1000g)
According to that: $molality =n(solute) / m(solvent) =\ \textgreater \ 4.8m = 4.8mole / 1kg$
= 4.8 mole * 98 g/mole = 470g
$m(H2SO4) = n(H2SO4)*Mr(H2SO4) =\ \textgreater \$ $=\ \textgreater \ Molarity = 4.8 mole / 1.2 L = 4 M$ m(H2SO4) which is =470g

m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =>
$Molarity = n(solute) / V(solution) =\ \textgreater \$

5 0

3 years ago