2/7=0.28571428571428571428571428571429
0.28571428571428571428571428571429*3=0.85714285714285714285714285714286
that is a long answer but it works
Length × Width = Area
-5*Width = 36
Simply divide 36 by 5 to get your answer
Hope that helps!!!!
Answer:
440 hours
Step-by-step explanation:
In this case the aircraft has completed one cycle of service in the first 454 hours of service. Then making the difference between the hours of service and the hours of the first cycle we have:
Hours of the second cycle= Total time in service- time Airworthiness Directive
=468-454=14
Then we have 14 hours of service and need to accumulate the rest to complete 454. It is
454-14=440
Then we need to accumulate 440 hours additional to complete the Airworthiness Directive .
<span>
y = 7 + 3/5
y = 35/5 + 3/5
y = 38/5
y = 2*(38/5)
y = 76/10
---
lunch time:
z = 1/2
z = 5*(1/2)
z = 5/10
---
time switching classes:
w = 7/10
---
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (76/10 - 5/10 - 7/10)/6
x = (76 - 5 - 7)/(10*6)
x = (64)/(10*6)
x = (2*2*2*2*2*2)/(2*5*2*3)
x = (2*2*2*2)/(5*3)
x = 16/15
x = 1.0666666666
---
check:
y = 7 + 3/5
y = 7.6
z = 1/2
z = 0.5
w = 7/10
w = 0.7
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (7.6 - 0.5 - 0.7)/6
x = 1.0666666666
answer:
1.07 hours</span>
