Answer:
2 M
Explanation:
The equation for molarity is "M = moles/liters"
Potassium chloride's atomic mass is 74.55, meaning one mole of KCl is equal to 74.55g. In the equation, 298g of KCl is being used. To find out how many moles this is, multiply 298g of KCl by (1 mol/74.55g of KCl) to get 4.0 moles. Now you can use the equation for molarity.
M = 4.0 moles/2 Liters
A continuous process by which rocks are created, changed from one form to another, destroyed, and then formed again into different types of rocks. But what really know is that it's a rocky situation.
200 ml is 1/5 of a liter, so the answer is five times the number of moles present in the solution. 0.6 moles/0.2 liter = x moles/1.0 liter. Solving for x gives 0.2 x = 0.6 or x = 3.0 M
so the answer is c
Answer:
Carbon dioxide and water I believe because it is a combustion reaction
Answer : The final equilibrium temperature of the water and iron is, 537.12 K
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
![q_1=-q_2](https://tex.z-dn.net/?f=q_1%3D-q_2)
![m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_f-T_1%29%3D-m_2%5Ctimes%20c_2%5Ctimes%20%28T_f-T_2%29)
where,
= specific heat of iron = 560 J/(kg.K)
= specific heat of water = 4186 J/(kg.K)
= mass of iron = 825 g
= mass of water = 40 g
= final temperature of water and iron = ?
= initial temperature of iron = ![352^oC=273+352=625K](https://tex.z-dn.net/?f=352%5EoC%3D273%2B352%3D625K)
= initial temperature of water = ![20^oC=273+20=293K](https://tex.z-dn.net/?f=20%5EoC%3D273%2B20%3D293K)
Now put all the given values in the above formula, we get:
![(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)](https://tex.z-dn.net/?f=%28825%5Ctimes%2010%5E%7B-3%7Dkg%29%5Ctimes%20560J%2F%28kg.K%29%5Ctimes%20%28T_f-625K%29%3D-%2840%5Ctimes%2010%5E%7B-3%7Dkg%29%5Ctimes%204186J%2F%28kg.K%29%5Ctimes%20%28T_f-293K%29)
![T_f=537.12K](https://tex.z-dn.net/?f=T_f%3D537.12K)
Therefore, the final equilibrium temperature of the water and iron is, 537.12 K