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Lapatulllka [165]
3 years ago
10

What is the mass of one mole of nitrogen atoms?

Chemistry
2 answers:
OLEGan [10]3 years ago
4 0

Answer:

28.0

Explanation:

Effectus [21]3 years ago
3 0

Answer:

14.01g

Explanation:

This depends on what periodic table you are using however if you use the official one used on the AP exam, it is 14.01g

Stoichiometry

1 mol N*14.01g/1 mol N

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A good example is the mineral<span> plagioclase. Plagioclase is a member of the feldspar group, but </span>there<span> is more than one type of plagioclase.</span>
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3 years ago
What is the molar mass of a gas if 0.281 g of the gas occupies a volume of 125 ml at a temperature 126 °c and a pressure of 777
AleksAgata [21]
<em>Answer :</em> 72.05 g/mol
<span>
<em>Explanation : </em>

Let's </span>assume that the given gas is an ideal gas. Then we can use ideal gas equation,<span>
PV = nRT<span>
</span>
Where, 
P = Pressure of the gas (Pa)
V = volume of the gas (m³)
n = number of moles (mol)
R = Universal gas constant (8.314 J mol</span>⁻¹ K⁻¹)<span>
T = temperature in Kelvin (K)
<span>
The given data for the gas </span></span>is,<span>
P = 777 torr = 103591 Pa
V = </span>125 mL = 125 x 10⁻⁶ m³<span>
T = (</span>126 + 273<span>) = 399 K
R = 8.314 J mol</span>⁻¹ K⁻¹<span>
n = ?

By applying the formula,
103591 Pa x  </span>125 x 10⁻⁶ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 399 K<span>
                                          n = 3.90 x 10</span>⁻³<span> mol

</span>Moles (mol) = mass (g) / molar mass (g/mol)<span>

Mass of the gas = </span><span>0.281 g
</span>Moles of the gas = 3.90 x 10⁻³ mol
<span>Hence,
   molar mass of the gas = mass / moles
                                          = 0.281 g / </span>3.90 x 10⁻³ mol
<span>                                          = 72.05 g/mol

</span>
7 0
3 years ago
Read 2 more answers
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Karolina [17]
Can you reword it im confused
6 0
2 years ago
Which of the following is an inexhaustible energy resource?
koban [17]
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4 0
2 years ago
A plasma membrane and a cell wall _____.
klemol [59]
<h3><u>Answer;</u></h3>

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3 years ago
Read 2 more answers
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